Identify the number of solutions to the quadratic equation x^2 - 2x + 1 = 0.

x^2 - 2x + 1 = 0; x^2 - 2x + 1 = (x - 1)^2; (x - 1)= 0; x = 0 + 1; x = 1

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Asked 5/6/2013 2:28:22 PM

Updated 6/20/2014 1:27:25 PM

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Edited by andrewpallarca [6/20/2014 1:27:33 PM]

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x^2 - 2x + 1 = 0;

x^2 - 2x + 1 = (x - 1)^2;

(x - 1)= 0;

x = 0 + 1;

x = 1

x^2 - 2x + 1 = (x - 1)^2;

(x - 1)= 0;

x = 0 + 1;

x = 1

Added 6/20/2014 1:27:25 PM

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