Question and answer
(6a + b)2
Question
Asked 12/6/2010 8:49:04 AM
Updated 9/28/2014 7:39:35 PM
7 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by janezeshun [9/26/2014 9:55:57 PM]
f
Original conversation
User: (6a + b)2

Weegy: 12z + 2b
RinatisDinoro|Points 250|

User: Simplify 5 + 2{x - 4[3x + 7(2 - x)]}.

Weegy: (3x-2) squared is 9x^2 - 12x + 4.
twistedechoes|Points 26|

User: 5 + 2{x - 4[3x + 7(2 - x)]}.

Weegy: x = 3
ambrosio_09|Points 725|

User: (y3 - 125) ÷ (y - 5)

Weegy: y = 31
Expert answered|RinatisDinoro|Points 250|

Question
Asked 12/6/2010 8:49:04 AM
Updated 9/28/2014 7:39:35 PM
7 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by janezeshun [9/26/2014 9:55:57 PM]
New answers
Rating
8
(6a + b)^2
= (6a+b)(6a+b)
= 36a^3 + 12ab + b^2
Added 9/26/2014 11:25:16 PM
This answer has been flagged as incorrect.
Flagged by yeswey [9/28/2014 7:39:11 PM]
8
5 + 2{x - 4[3x + 7(2 - x)]}
= 5 + 2x + 32x - 112
= (2x + 32x) + (5 + - 112)
= 34 + - 107
Added 9/26/2014 11:26:25 PM
This answer has been flagged as incorrect.
Flagged by yeswey [9/28/2014 7:34:26 PM]
8
5 + 2{x - 4[3x + 7(2 - x)]}
= 5 + 2[x - 4(3x + 14 - 7x)]
= 5 + 2[x - 4(14 - 4x)]
= 5 + 2(x - 56 + 16x)
= 5 + 2(17x - 56)
= 5 + 34x - 112
= 34x - 107
Added 9/28/2014 7:34:18 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [9/28/2014 11:11:47 PM]
8
(y^3 - 125) ÷ (y - 5)
=(y^3 - 5^3)/(y - 5)
= (y - 5)(y^2 + 5y + 25)/(y - 5)
= y^2 + 5y + 25
Added 9/28/2014 7:37:38 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [9/28/2014 11:12:04 PM]
8
(6a + b)^2 = 36a^2 + 12ab + b^2
Added 9/28/2014 7:39:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [9/28/2014 11:11:50 PM]
5
5 + 2{x - 4[3x + 7(2 - x)]}
= 5 + 2{ x -4[3x + 14 - 7x)]}
= 5 + 2{ x -4[14 - 4x]}
= 5 + 2{ x - 56 + 56x }
= 5 + 2{ 57x - 56}
= 5 + 114x - 112
= 114x - 107
Added 9/26/2014 10:00:12 PM
This answer has been flagged as incorrect.
Flagged by jeifunk [9/26/2014 11:27:07 PM]
5
(y^3 - 125) ÷ (y - 5)
=( y^3 - 5^3) / (y -5)
= (y -5) (y^2 - 5y +5^2)/(y -5)
= y^2 -5y +25
Added 9/26/2014 10:04:49 PM
This answer has been flagged as incorrect.
Confirmed by jeifunk [9/26/2014 11:27:56 PM], Flagged by yeswey [9/28/2014 7:37:42 PM]
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Questions asked by the same visitor
(6a + b)2
Weegy: 12z + 2b (More)
Question
Expert Answered
Updated 9/26/2014 9:25:23 PM
1 Answer/Comment
(6a + b)^2
= 36a^2 + 12ab +b^2
Added 9/26/2014 9:25:23 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [9/26/2014 11:41:34 PM], Rated good by jeifunk
y9 ÷ y3
Weegy: = y3 User: -mnp(3m - 5n + 7p) Weegy: why don't you do homeworks? you think you will cheat all your life? (More)
Question
Expert Answered
Updated 3/9/2014 12:51:08 PM
2 Answers/Comments
y9 ÷ y3

= y^6
Added 3/9/2014 12:50:03 PM
This answer has been confirmed as correct and helpful.
-mnp(3m - 5n + 7p)

= -3m^2np + 5mn^2p - 7mnp^2
Added 3/9/2014 12:51:08 PM
This answer has been confirmed as correct and helpful.
-mnp(3m - 5n + 7p)
Weegy: why don't you do homeworks? you think you will cheat all your life? User: (6a + b)^2 Weegy: The equation is not complete. Can you provide me with the whole equation so that I can give you a solution? (More)
Question
Expert Answered
Updated 3/9/2014 12:52:40 PM
2 Answers/Comments
-mnp(3m - 5n + 7p)

= -3m^2np + 5mn^2p - 7mnp^2
Added 3/9/2014 12:51:47 PM
This answer has been confirmed as correct and helpful.
(6a + b)^2

(6a + b)(6a + b)

36a^2 + 6ab + 6ab + b^2

= 36a^2 + 12ab + b^2
Added 3/9/2014 12:52:40 PM
This answer has been confirmed as correct and helpful.
48a3bc2 ÷ 3abc
Weegy: 5 (More)
Question
Expert Answered
Updated 3/9/2014 12:47:00 PM
1 Answer/Comment
(48a^3bc^2) ÷ (3abc)

= 16a^2c

Added 3/9/2014 12:46:59 PM
This answer has been confirmed as correct and helpful.
(2p + 7)(3p - 9)
Weegy: 6pp + 21p + 18 - 35 (More)
Question
Expert Answered
Updated 3/9/2014 12:48:15 PM
1 Answer/Comment
(2p + 7)(3p - 9)

6p^2 + 21p - 18p - 63

= 6p^2 + 3p - 63
Added 3/9/2014 12:48:15 PM
This answer has been confirmed as correct and helpful.
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