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Score: What is the equation of a circle whose center is at the origin and whose radius is 16? x2+ y2= 4 x2+ y2= 16 x2+ y2= 256
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Asked 7/25/2012 7:42:15 AM
Updated 7/1/2014 1:07:32 AM
1 Answer/Comment
Flagged by yeswey [7/1/2014 1:07:15 AM]
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User: Score: What is the equation of a circle whose center is at the origin and whose radius is 16? x2+ y2= 4 x2+ y2= 16 x2+ y2= 256

Question
Asked 7/25/2012 7:42:15 AM
Updated 7/1/2014 1:07:32 AM
1 Answer/Comment
Flagged by yeswey [7/1/2014 1:07:15 AM]
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The equation of a circle whose center is at the origin and whose radius is 16 is x^2+ y^2= 256

Added 7/1/2014 1:07:32 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/1/2014 1:29:43 AM]
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If y is 6 when x is 3 and y varies directly with x, the equation is y = kx where k is the constant. k = y/x = 6/3 = 2. The equation is y = 2x. When x = 8, y = 2(8) = 16.
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