Factor completely: 9X4

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Factor completely: 9X4 – 81X2

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Asked 9/9/2010 10:13:58 AM

Updated 1/4/2015 12:56:27 AM

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Flagged by yeswey [1/4/2015 12:55:58 AM]

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User: Factor completely: 9X4 – 81X2

Weegy: 9X4 – 81X2 = -126
Expert answered|MoStWaNteD|Points 1380|

Question

Asked 9/9/2010 10:13:58 AM

Updated 1/4/2015 12:56:27 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [1/4/2015 12:55:58 AM]

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yeswey

9x^4 – 81x^2 = 9x^2(x + 3)(x - 3)

Added 1/4/2015 12:56:27 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [1/4/2015 2:23:35 PM]

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Questions asked by the same visitor

Multiply: ( X + 4 )( X2 – 4X + 16)

Weegy: Best Answer - Chosen by Voters ((4/x) - (2/4x)) / ((1/2x) + (3/2x)) = ((16/4x) - (2/4x))/(4/2x) = (14/4x)/(2/x) = (14/4x) * (x/2) = 14x/8x = 14/8 = 7/4 (More)

Question

Updated 12/22/2014 12:07:35 PM

1 Answer/Comment

alfred123

(x + 4 )( x^2 – 4x + 16);

= x^3 - 4x^2 + 16x + 4x^2 - 16x + 64;

= x^3 + 64

Added 12/22/2014 12:07:25 PM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [12/22/2014 12:13:29 PM], Unconfirmed by andrewpallarca [12/22/2014 12:13:40 PM], Confirmed by andrewpallarca [12/22/2014 12:13:40 PM]

Multiply: (x + 4)(x^2 – 4x + 16)

Weegy: (x + 4)(x^2 – 4x + 16) = x^3 - 4x^2 + 16x + 4x^2 - 16x + 64 = x^3 + 64 (More)

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Updated 7/15/2018 10:20:42 AM

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