Question and answer
Factor completely: 9X4 – 81X2
Question
Asked 9/9/2010 10:13:58 AM
Updated 1/4/2015 12:56:27 AM
1 Answer/Comment
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Flagged by yeswey [1/4/2015 12:55:58 AM]
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User: Factor completely: 9X4 – 81X2

Weegy: 9X4 – 81X2 = -126
Expert answered|MoStWaNteD|Points 1380|

Question
Asked 9/9/2010 10:13:58 AM
Updated 1/4/2015 12:56:27 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [1/4/2015 12:55:58 AM]
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9x^4 – 81x^2 = 9x^2(x + 3)(x - 3)
Added 1/4/2015 12:56:27 AM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [1/4/2015 2:23:35 PM]
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Questions asked by the same visitor
Multiply: ( X + 4 )( X2 – 4X + 16)
Weegy: Best Answer - Chosen by Voters ((4/x) - (2/4x)) / ((1/2x) + (3/2x)) = ((16/4x) - (2/4x))/(4/2x) = (14/4x)/(2/x) = (14/4x) * (x/2) = 14x/8x = 14/8 = 7/4 (More)
Question
Updated 12/22/2014 12:07:35 PM
1 Answer/Comment
(x + 4 )( x^2 – 4x + 16);

= x^3 - 4x^2 + 16x + 4x^2 - 16x + 64;

= x^3 + 64
Added 12/22/2014 12:07:25 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [12/22/2014 12:13:29 PM], Unconfirmed by andrewpallarca [12/22/2014 12:13:40 PM], Confirmed by andrewpallarca [12/22/2014 12:13:40 PM]
Multiply: (x + 4)(x^2 – 4x + 16)
Weegy: (x + 4)(x^2 – 4x + 16) = x^3 - 4x^2 + 16x + 4x^2 - 16x + 64 = x^3 + 64 (More)
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Expert Answered
Updated 7/15/2018 10:20:42 AM
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