Which of the following equations has no solution? 3x+ 1 = 2x + 1 3x+ 1 = 3x+ 1 3x+ 1 = 3x+ 2
Question
Updated 11/29/2014 10:05:01 PM
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User: Which of the following equations has no solution? 3x+ 1 = 2x + 1 3x+ 1 = 3x+ 1 3x+ 1 = 3x+ 2

Weegy: 9x^4. If you are satisfied with my answer, please click 'Good' on the ratings. Thank you!
millizsen|Points 120|

Question
Updated 11/29/2014 10:05:01 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [11/29/2014 10:05:01 PM]
Rating
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The equation 3x + 1 = 3x + 2 has no solution.
3x + 1 = 3x + 2;
3x - 3x = 2 - 1;
0 = 1

Questions asked by the same visitor
Find the common difference of the sequence shown. , , 0, ... -1/8 -1/4 -1/2
Weegy: B.-1/4 is the answer. 1/2, 1/4 , 0, -1/4 is the sequence (More)
Question
Updated 8/28/2014 9:13:41 AM
The sequence 0,...-1/8, -1/4, -1/2 does not have a common difference, it has a common ratio.

Solve for x. 3(x + 5) - 2(x + 2) = 20 1 9 13
Weegy: Simplifying -6x + -2 = 40 Reorder the terms: -2 + -6x = 40 Solving -2 + -6x = 40 Solving for variable 'x'. Move all terms containing x to the left, [ all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -6x = 40 + 2 Combine like terms: -2 + 2 = 0 0 + -6x = 40 + 2 -6x = 40 + 2 Combine like terms: 40 + 2 = 42 -6x = 42 Divide each side by '-6'. x = -7 Simplifying x = -7 ] (More)
Question
Updated 9/14/2012 12:23:53 PM
3(x + 5) - 2(x + 2) = 20
3x + 15 - 2x - 4 = 20
3x - 2x = 20 -15 + 4
x = 9
Confirmed by andrewpallarca [1/22/2014 9:36:20 AM]
Find two consecutive integers whose sum is 67. Which of the following equations could be used to solve the problem? 2x= 67 2x+ 1 = 67 2x+ 2 = 67 x2+ 1= 67
Question
Updated 8/28/2014 9:30:22 AM
To find two consecutive integers whose sum is 67 use the equation 2x + 1= 67

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