Liquid nitrogen with a mass of 100 g at 77.3 K is stirred into a beaker containing 200 g of 5.00°C water. If the nitrogen leaves the solution as soon as it turns to gas, how much water freezes? (The latent heat of vaporization of nitrogen is 48.0 cal/g, and the latent heat of fusion of water is
79.6 cal/g.)

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Asked 8/24/2009 9:56:45 AM

Updated 8/2/2023 12:06:46 AM

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Heat absorbed = 100 g × 0.5 cal/g·K × (5.00°C - 77.3 K)

Heat released = 200 g × 1.00 cal/g·K × (0°C - 5.00°C)

Heat required to vaporize = 100 g × 48.0 cal/g

Calculate the heat required to freeze the water:

Heat required to freeze water = mass of water × latent heat of fusion of water

Heat required to freeze = 200 g × 79.6 cal/g

The amount of water that freezes is 5.0 g.

Added 8/2/2023 12:06:46 AM

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