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Heat absorbed = 100 g × 0.5 cal/g·K × (5.00°C - 77.3 K)
Heat released = 200 g × 1.00 cal/g·K × (0°C - 5.00°C)
Heat required to vaporize = 100 g × 48.0 cal/g
Calculate the heat required to freeze the water:
Heat required to freeze water = mass of water × latent heat of fusion of water
Heat required to freeze = 200 g × 79.6 cal/g
The amount of water that freezes is 5.0 g.
Added 119 days ago|8/2/2023 12:06:46 AM
This answer has been confirmed as correct and helpful.
