Can you state whether the parabola opens up or down and whether the Y coordinate of the vertex is the maximum or the minimum. f(x)=(x+3)(x+4)

f(x)=(x + 3)(x + 4) f(x) = x^2 + 3x + 4x + 12 f(x) = x^2 + 7x + 12 The parabola opens up and the vertex is the minimum . when x = -7/2 ,f(x) = -1/4 f(x) = (-7/2)^2 - 7/2*7 + 12 f(x) = -49/4 + 12 f(x) = -1/4 f(x) > = -1/4 .

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Asked 4/11/2013 8:54:41 AM

Updated 11/19/2014 8:54:57 PM

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f(x)=(x + 3)(x + 4)

f(x) = x^2 + 3x + 4x + 12

f(x) = x^2 + 7x + 12

The parabola opens up and the vertex is the minimum .

when x = -7/2 ,f(x) = -1/4

f(x) = (-7/2)^2 - 7/2*7 + 12

f(x) = -49/4 + 12

f(x) = -1/4

f(x) > = -1/4 .

f(x) = x^2 + 3x + 4x + 12

f(x) = x^2 + 7x + 12

The parabola opens up and the vertex is the minimum .

when x = -7/2 ,f(x) = -1/4

f(x) = (-7/2)^2 - 7/2*7 + 12

f(x) = -49/4 + 12

f(x) = -1/4

f(x) > = -1/4 .

Added 11/19/2014 8:54:57 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/20/2014 10:41:50 AM]

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