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When measuring sound intensity levels, the human ear's varying sensitivity to different frequencies is accounted for by using weighted scales like A-weighting, which adjusts measurements to reflect how humans perceive sound intensity across frequencies.
Added 8/15/2024 11:52:05 AM
This answer has been confirmed as correct and helpful.
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Solution:
F_{{net}} = m × a
F_{{net}} = 750 {kg} × 1.2 {m/s}^2 = 900 {N}
2000 {N} - F_{{friction}} = 900 {N}
F_{{friction}} = 2000 {N} - 900 {N} = 1100 {N}
Added 8/15/2024 11:54:47 AM
This answer has been confirmed as correct and helpful.
