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Find the least common multiple of x^3 - x^2 + x - 1 and x^2 - 1. Write the answer in factored form. A. (x + 1)2(x - 1) B. (x + 1)(x - 1)(x^2 + 1) C. (x^3 - x^2 + x - 1)(x^2 - 1) D. (x + 1)(x - 1)(x^2 - 1)
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Asked 10/1/2012 8:06:19 PM
Updated 4/24/2014 12:35:09 AM
1 Answer/Comment
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User: Find the least common multiple of x^3 - x^2 + x - 1 and x^2 - 1. Write the answer in factored form. A. (x + 1)2(x - 1) B. (x + 1)(x - 1)(x^2 + 1) C. (x^3 - x^2 + x - 1)(x^2 - 1) D. (x + 1)(x - 1)(x^2 - 1)





Question
Asked 10/1/2012 8:06:19 PM
Updated 4/24/2014 12:35:09 AM
1 Answer/Comment
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8
x^3 - x^2 + x - 1
= x^2(x - 1) + (x - 1)
= (x - 1)(x^2 + 1);

x^2 - 1 = (x + 1)(x - 1)

The least common multiple of x^3 - x^2 + x - 1 and x^2 - 1 is (x + 1)(x - 1)(x^2 + 1)
Added 4/24/2014 12:34:49 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/24/2014 12:37:17 AM]
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Solve by graphing. x2 +2x - 8 = 0
Weegy: Solve x2 - 2x - 8 = 0 by graphing. The x intercepts are - Algebra › Algebra › Coordinate-systemSOLUTION: Solve x2 - 2x - 8 = 0 by graphing. The x intercepts are ? and ?. [ Algebra -> Algebra -> Coordinate-system -> SOLUTION: Solve x2 - 2x - 8 = 0 by ... ] (More)
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Expert Answered
Updated 68 days ago|11/26/2022 12:24:35 AM
1 Answer/Comment
x^2 +2x - 8 = 0
(x - 2) ( x + 4) = 0
x = 2, x = - 2
Added 68 days ago|11/26/2022 12:24:30 AM
This answer has been confirmed as correct and helpful.
Simplify the sum. d^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 A. 2d62+15d+18/2d^2+d-88 B. d^2+14d+16 / (d+8)(d-8) C. 2d^2+14d+16/(d+8)(d-8) D. 2d^2+15d+18/(d+8)(d-8)
Weegy: A. 2d62+15d+18/2d^2+d-88 is the answer. (More)
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Expert Answered
Asked 10/1/2012 7:43:29 PM
0 Answers/Comments
the sum. d^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 A. d^2+14d+16 / (d+8)(d-8) B. 2d^2+14d+16/(d+8)(d-8) C. 2d^2+15d+18/(d+8)(d-8)
Question
Not Answered
Updated 4/24/2014 12:41:55 AM
1 Answer/Comment
(d^2+d-30)/(d^2+3d-40) + (d^2+14d+48)/(d^2-2d-48)
= (d - 5)(d + 6)/(d + 8)(d - 5) + (d + 6)(d + 8)/(d - 8)(d + 6)
= (d + 6)/(d + 8) + (d + 8)/(d - 8)
= (d + 6)(d - 8)/(d + 8)(d - 8) + (d + 8)(d + 8)/(d - 8)(d + 8)
= (d^2 - 2d - 48)/(d + 8)(d - 8) + (d^2 + 16d + 64)/(d + 8)(d - 8)
= (2d^2 + 14d + 16)/(d + 8)(d - 8)
Added 4/24/2014 12:41:51 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/24/2014 12:43:37 AM]
Use the Binomial Theorem to expand the binomial. (x + 2y^2)3 A. x3 - 3x^2y2 + 3xy^4 - y^6 B. x3 + 6^x2y2 + 12xy^4 + 8y^6 C. x3 - 6x^2y2 + 12xy^4 - 8y^6 w D. x3 + 3x^2y^2 + 3xy^4 + y6
Weegy: C. x3 - 6x^2y2 + 12xy^4 - 8y^6 (More)
Question
Expert Answered
Updated 6/10/2014 11:44:25 PM
1 Answer/Comment
(x + 2y^2)^3
= x^3 + 3x^2(2y^2) + 3x(2y^2)^2 + (2y^2)^3
= x^3 + 6x^2y^2 + 12xy^4 + 8y^6
Added 6/10/2014 11:44:22 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/10/2014 11:54:09 PM]
What is the expression in factored form? 16x^2 - 25 A. (4x - 5)2 B. (4x + 5)(-4x - 5) C. (4x + 5)(4x - 5) D. (-4x + 5)(4x - 5)
Question
Not Answered
Updated 7/30/2014 10:03:25 AM
1 Answer/Comment
16x^2 - 25 = (4x + 5)(4x - 5)
Added 7/30/2014 10:03:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/30/2014 10:05:16 AM]
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