Indicate in standard form the equation of the line passing through the given points. L(5, 0), M(0, 5)
The standard form the equation of the line passing through the given points. L(5, 0), M(0, 5) is x + y = 5 . slope = (5 - 0)/(0 - 5) = -1 y = -x + 5 x + y = 5
Question
Updated 2/10/2015 4:47:06 AM
Rating
3
The standard form the equation of the line passing through the given points. L(5, 0), M(0, 5) is x + y = 5 .
slope = (5 - 0)/(0 - 5) = -1
y = -x + 5
x + y = 5
Confirmed by Andrew. [2/10/2015 4:51:55 AM]

Questions asked by the same visitor
Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (0, - 3) interior exterior on the circle User: The equation of the circle whose center is (0, 0) and radius is length 9 is x² + y² = 3 x² + y² = 9 x² + y² = 81
Weegy: The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)? + (y - 1)? = 9. User: Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (5, -3) interior exterior on the circle Weegy: 1.4 - (-3.6) = 1.4 + 3.6; = 5 User: Find the coordinates of the center of the following circle. (x - 5)² + (y + 3)² = 25 (5, 3) (-5, 3) (5, -3) Weegy: -3x(-3)-(-5) = 9x + 5 User: Enter the equation of the circle described below. Center (5, 2), radius = 3 User: Enter the equation of the circle described below. Center (3, -2), radius = 5 User: Enter the equation of the circle described below. Center (-3, 0), radius Weegy: The equation of a circle with a center at (-3,0) and a radius of square root of 5 is (x + 3)^2 + y^2 = 5. User: Enter the equation of the circle described below. Center (0, 0), radius = 4 (More)
Question
Updated 2/2/2015 10:09:23 PM
The point (0, - 3) is on the circle (x - 5)^2 + (y + 3)^2 = 25.
(0 - 5)^2 + (-3 + 3)^2 = (-5)^2 + 0^2 = 25, so its on the circle.
Confirmed by jeifunk [2/3/2015 1:38:50 AM]
The equation of the circle whose center is (0, 0) and radius is length 9 is x² + y² = 81.
Confirmed by jeifunk [2/3/2015 1:39:04 AM]
The point (5, -3) is interior the circle (x - 5)^2 + (y + 3)^2 = 25.
Confirmed by jeifunk [2/3/2015 1:39:18 AM]
The coordinates of the center of the circle (x - 5)² + (y + 3)² = 25 is (5, -3).
Confirmed by jeifunk [2/3/2015 1:39:27 AM]
Tthe equation of the circle with Center (0, 0), radius = 4 is x^2 + y^2 = 16
Confirmed by jeifunk [2/3/2015 1:39:35 AM]
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