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3ay(a + 2y)2 =
3ay(a + 2y)^2 = 3a^3y + 12a^2y^2 + 12ay^3
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Asked 3/16/2016 9:35:49 AM
Updated 3/16/2016 9:48:08 AM
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3ay(a + 2y)^2 = 3a^3y + 12a^2y^2 + 12ay^3
Added 3/16/2016 9:48:08 AM
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Questions asked by the same visitor
Factor the following polynomial completely. 20x2 + 22xy + 6y2 =
Question
Not Answered
Updated 3/16/2016 10:25:21 AM
1 Answer/Comment
20x^2 + 22xy + 6y^2 = 2(2x + y)(5x + 3y)
Added 3/16/2016 10:25:21 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [3/16/2016 10:25:53 AM]
Perform the indicated operation. (2x - 4y)(2x + 4y)
Weegy: 2x - 4y for x = 2 and y = 4; 2(2) - 4(4) = 4 - 16 = -12 User: Simplify. x2(2x3 - 3) - 3x(x + 4) User: Write the nth term of the following sequence in terms of the first term of the sequence. 1, 8, 15, 22, . . . (More)
Question
Not Answered
Updated 3/16/2016 11:52:16 PM
4 Answers/Comments
(2x - 4y)(2x + 4y)
= 2x*2x - 4y*2x + 2x*4y - 4y*4y
= 4x^2 - 8xy + 8xy - 16y^2
= 4x^2 - 16y^2
Added 3/16/2016 6:43:13 PM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [3/16/2016 11:49:26 PM], Rated good by Andrew.
x^2(2x^3 - 3) - 3x(x + 4)
= x^2*2x^3 - x^2*3 - 3x*x - 3x*4
= 2x^5 - 3x^2 - 3x^2 - 12x
= 2x^5 - 12x
Added 3/16/2016 6:43:57 PM
This answer has been flagged as incorrect.
Flagged by Andrew. [3/16/2016 11:52:21 PM]
Write the nth term of the following sequence in terms of the first term of the sequence 1, 8, 15, 22, . . . is 7n - 6.
The common difference = 22 - 15 = 7;
nth term = 1 + (n - 1)*7 = 7n - 7 + 1 = 7n - 6
Added 3/16/2016 6:44:53 PM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [3/16/2016 11:52:43 PM], Rated good by Andrew.
x^2(2x^3 - 3) - 3x(x + 4)
= 2x^5 - 3x^2 - 3x^2 - 12x
= 2x^5 - 6x^2 - 12x
Added 3/16/2016 11:52:16 PM
This answer has been confirmed as correct and helpful.
Work the item as directed. Factor 24x2 - 6xy -63y2 completely.
Question
Not Answered
Updated 3/16/2016 8:58:05 PM
1 Answer/Comment
24x^2 - 6xy - 63y^2;
= 4x*6x - 7y*6x + 4x*9y - 7y*9y;
= (4x - 7y)(6x + 9y)
Added 3/16/2016 8:58:05 PM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [3/16/2016 10:22:31 PM], Rated good by Andrew.
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