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Solution:

x/3 + 1/2 = x/6

x/3 - x/6 = -1/2

2x-x/6 = -1/2

x/6 = -1/2

x = -1/2*6

x = -6/2 or -3

x/3 + 1/2 = x/6

x/3 - x/6 = -1/2

2x-x/6 = -1/2

x/6 = -1/2

x = -1/2*6

x = -6/2 or -3

Added 3/3/2023 8:32:30 PM

This answer has been confirmed as correct and helpful.

Two numbers have a sum of 71. If one number is v, represent the other number as an expression of v. **Weegy:** Two numbers have a sum of 71. If one number is v,(71-v) is the other number as an expression of v. (More)

Question|Asked by Su_Akemi

Expert Answered

Asked 3/3/2023 6:26:58 PM

0 Answers/Comments

Solve the equation 5 +3=8 +11
. x=? **Weegy:** x + 10 = 15 ; x = 15 - 10 ; x = 5 **User:** 5x+3=8x+11 **Weegy:** 8x - 1 = 5x + 23 ;
8x - 5x = 23 + 1 ;
3x = 24 ;
x = 24/3 ;
x = 8 **User:** Solve the equation 5x+3=8x+11. What is x? **Weegy:** 8x - 1 = 5x + 23 ; 8x - 5x = 23 + 1 ; 3x = 24 ; x = 24/3 ; x = 8 (More)

Question|Asked by Su_Akemi

Expert Answered

Updated 3/3/2023 7:10:45 PM

1 Answer/Comment

5x+3=8x+11

5x - 8x = 11 -3

-3x = 8

x = -8/3

5x - 8x = 11 -3

-3x = 8

x = -8/3

Added 3/3/2023 7:10:17 PM

This answer has been confirmed as correct and helpful.

The distance (in miles) traveled when driving at a certain speed s for 23 hours, then driving 5 miles/hour faster for another hour. Express the distance in terms of s
.

Question|Asked by Su_Akemi

Not Answered

Updated 3/3/2023 7:48:01 PM

1 Answer/Comment

d = d1 + d2

d1 = 23s

d2 = 1*(s+5) = s+5

d = d1 + d2 = 23s + s + 5 = 24s +5

when s = 40, this becomes:

d1 = 23 * 40 = 920

d2 = 40 + 5 = 43

d1 + d2 = 920 + 43 = 963 = d

d1 = 23s

d2 = 1*(s+5) = s+5

d = d1 + d2 = 23s + s + 5 = 24s +5

when s = 40, this becomes:

d1 = 23 * 40 = 920

d2 = 40 + 5 = 43

d1 + d2 = 920 + 43 = 963 = d

Added 3/3/2023 7:48:01 PM

This answer has been confirmed as correct and helpful.

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