Question and answer
23/5
Question|Asked by Su_Akemi
Asked 3/3/2023 7:23:28 PM
Updated 3/3/2023 8:32:30 PM
1 Answer/Comment
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Original conversation
User: 23/5

Weegy: 23/5 = 4.6
|Score 1|jeifunk|Points 93064|

User: x/3 + 1/2 = x/6

Weegy: 6 x 23 = 138
|Score .8006|yeswey|Points 33079|

Question|Asked by Su_Akemi
Asked 3/3/2023 7:23:28 PM
Updated 3/3/2023 8:32:30 PM
1 Answer/Comment
New answers
Rating
3
Solution:
x/3 + 1/2 = x/6
x/3 - x/6 = -1/2
2x-x/6 = -1/2
x/6 = -1/2
x = -1/2*6
x = -6/2 or -3
Added 3/3/2023 8:32:30 PM
This answer has been confirmed as correct and helpful.
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Questions asked by Su_Akemi
Two numbers have a sum of 71. If one number is v, represent the other number as an expression of v.
Weegy: Two numbers have a sum of 71. If one number is v,(71-v) is the other number as an expression of v. (More)
Question|Asked by Su_Akemi
Expert Answered
Asked 3/3/2023 6:26:58 PM
0 Answers/Comments
Solve the equation 5 +3=8 +11 . x=?
Weegy: x + 10 = 15 ; x = 15 - 10 ; x = 5 User: 5x+3=8x+11 Weegy: 8x - 1 = 5x + 23 ; 8x - 5x = 23 + 1 ; 3x = 24 ; x = 24/3 ; x = 8 User: Solve the equation 5x+3=8x+11. What is x? Weegy: 8x - 1 = 5x + 23 ; 8x - 5x = 23 + 1 ; 3x = 24 ; x = 24/3 ; x = 8 (More)
Question|Asked by Su_Akemi
Expert Answered
Updated 3/3/2023 7:10:45 PM
1 Answer/Comment
5x+3=8x+11
5x - 8x = 11 -3
-3x = 8
x = -8/3
Added 3/3/2023 7:10:17 PM
This answer has been confirmed as correct and helpful.
The distance (in miles) traveled when driving at a certain speed s for 23 hours, then driving 5 miles/hour faster for another hour. Express the distance in terms of s .
Question|Asked by Su_Akemi
Not Answered
Updated 3/3/2023 7:48:01 PM
1 Answer/Comment
d = d1 + d2
d1 = 23s
d2 = 1*(s+5) = s+5
d = d1 + d2 = 23s + s + 5 = 24s +5

when s = 40, this becomes:

d1 = 23 * 40 = 920
d2 = 40 + 5 = 43
d1 + d2 = 920 + 43 = 963 = d
Added 3/3/2023 7:48:01 PM
This answer has been confirmed as correct and helpful.
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