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Write 5,000,039 in scientific notation. 0.5000039 x 10^-7 5.000039 x 10^-6 5.000039 x 10^6 0.5000039 x 10^7
5,000,039 in scientific notation is 5.000039 x 10^6
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Expert answered|jeifunk|Points 48261|
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Asked 5/4/2015 8:44:12 AM
Updated 5/4/2015 10:06:18 AM
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This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [5/4/2015 10:06:18 AM]
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Questions asked by the same visitor
Is the real number sqrt 1.21 rational or irrational?
Weegy: sqrt 1.21 is a rational number. Its fraction form is 11/10. (More)
Question
Expert Answered
Asked 5/4/2015 8:45:03 AM
0 Answers/Comments
Solve this quadratic equation using the quadratic formula. x^2 + 8x - 5 = 0
Question
Updated 5/8/2015 11:55:50 AM
1 Answer/Comment
x^2 + 8x - 5 = 0
a = 1, b = 8, c = -5
b^2 - 4ac = 8^2 - 4(1)(-5) = 64 + 20 = 84
x = [-b ± sqrt (b^2 - 4ac)]/2a
= (-8 ± sqrt 84)/2
= (-8 ± 2 sqrt 21)/2
= -4 ± sqrt 21
Added 5/8/2015 9:21:05 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [5/8/2015 11:56:04 AM]
What is the solution set of (x - 2)(x - 3) = 2?
Weegy: 6(x - 2) = 4 6x - 12 = 4; 6x = 4 + 12; 6x = 16; x = 16/6; x = 8/3 User: The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of the resulting rectangle is 24 square inches. What is the area of the original rectangle? 12 square inches 48 square inches 96 square inches (More)
Question
Updated 5/9/2015 11:59:40 AM
1 Answer/Comment
(x - 2)(x - 3) = 2;
x^2 - 3x - 2x + 6 = 2;
x^2 - 5x + 6 - 2 = 0;
x^2 - 5x + 4 = 0;
(x - 1)(x - 4) = 0;
x - 1 = 0;
x = 1;
x - 4 = 0;
x = 4;
The solution set is x = 1 or x = 4.
Added 5/9/2015 11:59:40 AM
This answer has been confirmed as correct and helpful.
Simplify (6ab^3c)(-abc^2).
Weegy: (6ab^3c)(-abc^2) = -6a^2b^4c^3 User: Identify all the points that are on the following quadratic function: y = x^2 - 3x (0,3) (0,0) (2,-2) (-1,4) (-3,15) (More)
Question
Updated 5/4/2015 10:21:48 AM
1 Answer/Comment
(0,0) (2,-2) (-1,4) are on the following quadratic function: y = x^2 - 3x.
when x = 0, y = 0^2 - 3(0) = 0 - 0 = 0
when x = 2, y = 2^2 - 3(2) = 4 - 6 = -2
when x = -1, y = (-1)^2 - 3(-1) = 1 + 3 = 4
Added 5/4/2015 10:14:04 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [5/4/2015 10:22:31 AM]
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