4/5 x 1 1/6
Question
Updated 6/12/2014 5:13:13 PM
Original conversation
User: 4/5 x 1 1/6

Weegy: x+(4)/(x)+2=x+(1)/(x)+5 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is x. [ Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. x+(4)/(x)+2=x*(x)/(x)+(1)/(x)+5*(x)/(x) Multiply x by x to get x^(2). x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+5*(x)/(x) Multiply 5 by x to get 5x. x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+(5x)/(x) Combine the numerators of all expressions that have common denominators. x+(4)/(x)+2=(x^(2)+1+5x)/(x) Reorder the polynomial x^(2)+1+5x alphabetically from left to right, starting with the highest order term. x+(4)/(x)+2=(x^(2)+5x+1)/(x) Find the LCD (least common denominator) of x+(4)/(x)+2+((x^(2)+5x+1))/(x). Least common denominator: x Multiply each term in the equation by x in order to remove all the denominators from the equation. x*x+(4)/(x)*x+2*x=(x^(2)+5x+1)/(x)*x Cancel the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+(4)/( x )* x +2*x=(x^(2)+5x+1)/(x)*x Reduce the expression by removing the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply x by x to get x^(2). x^(2)+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply 4 by 1 to get 4. x^(2)+4+2*x=(x^(2)+5x+1)/(x)*x Multiply 2 by x to get 2x. x^(2)+4+2x=(x^(2)+5x+1)/(x)*x Reorder the polynomial x^(2)+4+2x alphabetically from left to right, starting with the highest order term. x^(2)+2x+4=(x^(2)+5x+1)/(x)*x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1)/( x )* x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1) Remove the parentheses around the expression x^(2)+5x+1. x^(2)+2x+4=x^(2)+5x+1 Since x^(2) contains the variable to solve for, move it to the left-hand side of the equation by subtracting x^(2) from both sides. x^(2)+2x+4-x^(2)=5x+1 Since 5x contains the variable to solve for, move it to the left-hand side of the ]
thederby|Points 1530|

User: 4/5 x 1 1/6

Weegy: x+(4)/(x)+2=x+(1)/(x)+5 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is x. [ Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. x+(4)/(x)+2=x*(x)/(x)+(1)/(x)+5*(x)/(x) Multiply x by x to get x^(2). x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+5*(x)/(x) Multiply 5 by x to get 5x. x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+(5x)/(x) Combine the numerators of all expressions that have common denominators. x+(4)/(x)+2=(x^(2)+1+5x)/(x) Reorder the polynomial x^(2)+1+5x alphabetically from left to right, starting with the highest order term. x+(4)/(x)+2=(x^(2)+5x+1)/(x) Find the LCD (least common denominator) of x+(4)/(x)+2+((x^(2)+5x+1))/(x). Least common denominator: x Multiply each term in the equation by x in order to remove all the denominators from the equation. x*x+(4)/(x)*x+2*x=(x^(2)+5x+1)/(x)*x Cancel the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+(4)/( x )* x +2*x=(x^(2)+5x+1)/(x)*x Reduce the expression by removing the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply x by x to get x^(2). x^(2)+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply 4 by 1 to get 4. x^(2)+4+2*x=(x^(2)+5x+1)/(x)*x Multiply 2 by x to get 2x. x^(2)+4+2x=(x^(2)+5x+1)/(x)*x Reorder the polynomial x^(2)+4+2x alphabetically from left to right, starting with the highest order term. x^(2)+2x+4=(x^(2)+5x+1)/(x)*x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1)/( x )* x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1) Remove the parentheses around the expression x^(2)+5x+1. x^(2)+2x+4=x^(2)+5x+1 Since x^(2) contains the variable to solve for, move it to the left-hand side of the equation by subtracting x^(2) from both sides. x^(2)+2x+4-x^(2)=5x+1 Since 5x contains the variable to solve for, move it to the left-hand side of the ]
thederby|Points 1530|

User: 8(6-5) + 10

Weegy: 8(6-5) + 10 48-40+10 8+10 =18

User: 4(-2)² + 8(-2) + 3(-2) + 6

Weegy: 4(4) + -16 + -6 + 6 16+ -16 Answer is 0

User: (1/3)9³

Weegy: (1/3)9³ The answer is (9X9X9) divided by 3 =81X3 = 243

User: -11(3/2)(.12(-12))

Weegy: (-11) * (3 / 2) * (.12 * (-12)) = 23.76

Question
Updated 6/12/2014 5:13:13 PM
Rating
3
4/5 x 1 1/6

= 4/5 * 7/6

= (4 * 7) / (5 * 6)

= 28/30

= 14/15
Confirmed by debnjerry [6/12/2014 5:31:59 PM]

Questions asked by the same visitor
4/5 x 1 1/6 =
Weegy: User: (-17) - (-22) = (More)
Question
Updated 8/14/2014 5:57:46 AM
4/5 * 1 1/6

= 4/5 * 7/6;

= 28/30;

= 14/15
Confirmed by yumdrea [8/13/2014 1:41:37 PM]
(-17) - (-22) = -17 + 22 = 5
Confirmed by yumdrea [8/13/2014 1:41:57 PM]
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