Question and answer
Select the product of (-6x7y)(x3y5)
(-6x^7y)(x^3y^5) = -6x^7*x^3*y^5*y = -6x^10y^6
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Asked 11/23/2014 2:03:06 PM
Updated 11/24/2014 6:08:25 AM
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(-6x^7y)(x^3y^5)
= -6x^7*x^3*y^5*y
= -6x^10y^6
Added 11/24/2014 6:08:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [11/28/2014 1:57:22 AM], Rated good by andrewpallarca
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Questions asked by the same visitor
Select the difference of (8x2 - 3x3) - (2x2 - 5x3). 8x6 8x5 6x2 - 8x3 6x2 + 2x3
Question
Updated 11/22/2014 6:44:41 PM
1 Answer/Comment
(8x^2 - 3x^3) - (2x^2 - 5x^3)
= 8x^2 - 3x^3 - 2x^2 + 5x^3
= 6x^2 + 2x^3
Added 11/22/2014 6:44:41 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/23/2014 12:45:41 AM]
what is the difference of (8x2 - 3x3) - (2x2 - 5x3). 8x6 8x5 6x2 - 8x3 6x2 + 2x3
Question
Updated 11/17/2014 3:30:38 PM
1 Answer/Comment
(8x^2 - 3x^3) - (2x^2 - 5x^3)

=8x^2 - 3x^3 - 2x^2 + 5x^3;

= 6x^2 + 2x^3
Added 11/17/2014 3:30:38 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [11/20/2014 8:54:17 AM]
5*2^2 =
Question
Not Answered
Updated 11/17/2014 9:07:25 PM
1 Answer/Comment

5*2^2 = 20

Added 11/17/2014 9:07:25 PM
This answer has been confirmed as correct and helpful.
Select the difference of (8x^2 - 3x^3) - (2x^2 - 5x^3)
Weegy: (2x^2 - 3x^3) - (8x^2 - 5x^3) = (2x^2 - 3x^3) + (-8x^2 + 5x^3) = 2x^3 - 6x^2 User: Simplify the following expression. 2(8x + 2) Weegy: 2(8x + 2) = (2)(8x) + (2)(2) = 16x + 4 User: Select the product of (5x - 4)(5x + 9). (More)
Question
Updated 11/20/2014 1:01:14 PM
3 Answers/Comments
(5x - 4)(5x + 9)
= 5x*5x - 4*5x + 5x*9 - 4*9
= 25x^2 - 20x + 45x - 36
= 25x^2 + 25x - 36
Added 11/20/2014 5:42:20 AM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [11/20/2014 8:52:32 AM], Rated good by andrewpallarca
-7w^3 + 6w^2 - 9w - 21w^2 + 18w - 27
Weegy: -7w^3 + 6w^2 - 9w - 21w^2 + 18w-27 = (-7w^3) + (6w^2 + -21w^2) + (-9w + 18w) + (-27) = -7w^3 - 15w^2 + 9w - 27 (More)
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Expert Answered
Updated 11/28/2014 1:56:52 AM
0 Answers/Comments
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