What is the solution set of (3x - 1)2 = 5?
Question
Updated 7/7/2014 5:42:39 PM
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Flagged by andrewpallarca [7/7/2014 5:42:39 PM]
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User: What is the solution set of (3x - 1)2 = 5?

Weegy: x=-(2)/(3),2 is the answer... 3x^(2)-4x=4 To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side. 3x^(2)-4x-4=0.. Find the factors such that the product of the factors is the trinomial 3x^(2)-4x-4. [ This can be done by trial and error and checked using the FOIL method of simplifying polynomials. (3x+2)(x-2)=0.. Set each of the factors of the left-hand side of the equation equal to 0. 3x+2=0_x-2=0... Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides. 3x=-2_x-2=0... Divide each term in the equation by 3. (3x)/(3)=-(2)/(3)_x-2=0... Simplify the left-hand side of the equation by canceling the common factors. x=-(2)/(3)_x-2=0... Set each of the factors of the left-hand side of the equation equal to 0. x=-(2)/(3)_x-2=0... Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2 to both sides. x=-(2)/(3)_x=2... The complete solution is the set of the individual solutions. x=-(2)/(3),2.. ]

Question
Updated 7/7/2014 5:42:39 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [7/7/2014 5:42:39 PM]
Rating
3
(3x - 1)^2 = 5;
9x^2 - 6x + 1 = 5;
9x^2 - 6x + 1 - 5 = 0;
9x^2 - 6x - 4 = 0;
x(9x - 6) - 4
x = 1/3(1 - sqrt 5) or x = 1/3(x + sqrt 5)

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