Question and answer
5y2 - 2y - 3
Question
Asked 6/10/2013 9:00:57 AM
Updated 6/5/2014 11:56:14 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [6/5/2014 11:55:17 PM]
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Original conversation
User: 8y^2 + 6y + 1

User: 5y2 - 2y - 3

Weegy: (5y + 3)(y - 1)
Indame|Points 30|

User: 7x2 - 9x - 10

Weegy: 5 - 2(-4)/9(-4) + (-4)(5) = -167/9 or -18 5/9 (-18.56)
andrewpallarca|Points 22403|

Question
Asked 6/10/2013 9:00:57 AM
Updated 6/5/2014 11:56:14 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [6/5/2014 11:55:17 PM]
New answers
Rating
8
8y^2 + 6y + 1 = (2y + 1)(4y + 1)
Added 6/5/2014 11:55:31 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/2/2014 1:13:56 PM]
8
7x^2 - 9x - 10 = (x - 2)(7x + 5)
Added 6/5/2014 11:56:14 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/2/2014 1:14:12 PM]
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Questions asked by the same visitor
Find the product of (5a - 7)(2a - 1)?
Question
Updated 1/28/2018 7:24:33 AM
1 Answer/Comment
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
Question
Updated 7/3/2014 8:38:35 PM
1 Answer/Comment
The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Added 7/3/2014 8:38:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Not Answered
Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
Write the equation of the given circle. center (1, -5) radius of 10
Question
Not Answered
Updated 7/3/2014 8:34:36 PM
1 Answer/Comment
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Added 7/3/2014 8:34:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
32,803,472
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