Multiply these binomials: (6x + 7)(20x

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Multiply these binomials: (6x + 7)(20x – 9)=

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Asked 1/16/2013 10:30:09 AM

Updated 6/3/2014 11:28:58 PM

5 Answers/Comments

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Flagged by yeswey [6/3/2014 11:27:59 PM]

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User: Multiply these binomials: (6x + 7)(20x – 9)=

Weegy: (6x + 7)(20x ? 9) = 120x^2 + 86x - 63.
eturker|Points 2852|

User: Multiply these binomials: (10x – 11)(–14x + 9)

Weegy: (10x ? 11)(?14x + 9) = -140x^2 + 244x - 99.
eturker|Points 2852|

User: Multiply these binomials: (16x + 13)(–8x + 15)=

Weegy: (16x ? 19)(8x ? 8) = 128x^2 - 280x + 152.
eturker|Points 2852|

User: Multiply these binomials: (6x – 3)(–5x + 2)=

Weegy: x=-1 and x=-1/5 for the equation 5x^2+6x=-1
migzptz|Points 7292|

User: Multiply these binomials: (18x + 20)(–12x – 6)=

Question

Asked 1/16/2013 10:30:09 AM

Updated 6/3/2014 11:28:58 PM

5 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [6/3/2014 11:27:59 PM]

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yeswey

(6x + 7)(20x – 9)
= 120x^2 - 54x + 140x - 63
= 120x^2 + 86x - 63

Added 6/3/2014 11:22:27 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/20/2014 1:24:38 PM]

yeswey

(10x – 11)(–14x + 9)
= -140x^2 + 90x + 154x - 99
= -140x^2 + 244x - 99

Added 6/3/2014 11:23:39 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/20/2014 1:25:00 PM]

yeswey

(16x + 13)(–8x + 15)
= -128x^2 + 240x - 104x + 195
= -128x^2 + 136x + 195

Added 6/3/2014 11:25:13 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/20/2014 1:27:40 PM]

yeswey

(6x – 3)(–5x + 2)
= -30x^2 + 12x + 15x - 6
= -30x^2 + 27x - 6

Added 6/3/2014 11:26:56 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/20/2014 1:27:51 PM]

yeswey

(18x + 20)(–12x – 6)
= -216x^2 - 108x - 240x - 120
= -216x^2 - 348x - 120

Added 6/3/2014 11:28:58 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/20/2014 1:29:04 PM]

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Add the following polynomials: (x^2 – x + 7) + (x^2 + 3x + 1) a. 2x^2+2x-8 b. 2x^2+2x+8 c. 2x^2-2x+8 d. -2x^2+2x+8

Weegy: (x^2 – x + 7) + (x^2 + 3x + 1) = b. 2x^2+2x+8 (More)

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Expert Answered

Updated 5/31/2014 2:58:24 PM

0 Answers/Comments

Add the following polynomials: (x^2 – x + 7) + (x^2 + 3x + 1) a. 2x^2+2x-8 b. 2x^2+2x+8 c. 2x^2-2x+8 d. -2x^2+2x+8

Weegy: (x^2 - x + 7) + (x^2 + 3x + 1) = 2x^2 + 2x + 8 User: Add the following polynomials: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) a. -5x^2-7x+5 b. 5x^2-7x+5 c. -5x^2+7x+5 d. 5x^2-7x-5 (More)

Question

Updated 8/1/2014 12:52:16 PM

1 Answer/Comment

andrewpallarca

(–3x^2 + 3x + 3) + (–2x^2 – 10x + 2)
= -5x^2 - 7x + 5

Added 8/1/2014 12:52:16 PM

This answer has been confirmed as correct and helpful.

Add the following polynomials: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) a. -5x^2-7x+5 b. 5x^2-7x+5 c. -5x^2+7x+5 d. 5x^2-7x-5

Weegy: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) = -5x^2 - 7x + 5 (More)

Question

Expert Answered

Updated 8/1/2014 12:50:54 PM