Question and answer
Multiply these binomials: (6x + 7)(20x – 9)=
Question
Asked 1/16/2013 10:30:09 AM
Updated 6/3/2014 11:28:58 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [6/3/2014 11:27:59 PM]
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Original conversation
User: Multiply these binomials: (6x + 7)(20x – 9)=

Weegy: (6x + 7)(20x ? 9) = 120x^2 + 86x - 63.
eturker|Points 2852|

User: Multiply these binomials: (10x – 11)(–14x + 9)

Weegy: (10x ? 11)(?14x + 9) = -140x^2 + 244x - 99.
eturker|Points 2852|

User: Multiply these binomials: (16x + 13)(–8x + 15)=

Weegy: (16x ? 19)(8x ? 8) = 128x^2 - 280x + 152.
eturker|Points 2852|

User: Multiply these binomials: (6x – 3)(–5x + 2)=

Weegy: x=-1 and x=-1/5 for the equation 5x^2+6x=-1
migzptz|Points 7292|

User: Multiply these binomials: (18x + 20)(–12x – 6)=







Question
Asked 1/16/2013 10:30:09 AM
Updated 6/3/2014 11:28:58 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [6/3/2014 11:27:59 PM]
New answers
Rating
8
(6x + 7)(20x – 9)
= 120x^2 - 54x + 140x - 63
= 120x^2 + 86x - 63
Added 6/3/2014 11:22:27 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/20/2014 1:24:38 PM]
8
(10x – 11)(–14x + 9)
= -140x^2 + 90x + 154x - 99
= -140x^2 + 244x - 99
Added 6/3/2014 11:23:39 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/20/2014 1:25:00 PM]
8
(16x + 13)(–8x + 15)
= -128x^2 + 240x - 104x + 195
= -128x^2 + 136x + 195
Added 6/3/2014 11:25:13 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/20/2014 1:27:40 PM]
8
(6x – 3)(–5x + 2)
= -30x^2 + 12x + 15x - 6
= -30x^2 + 27x - 6
Added 6/3/2014 11:26:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/20/2014 1:27:51 PM]
8
(18x + 20)(–12x – 6)
= -216x^2 - 108x - 240x - 120
= -216x^2 - 348x - 120
Added 6/3/2014 11:28:58 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/20/2014 1:29:04 PM]
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Add the following polynomials: (x^2 – x + 7) + (x^2 + 3x + 1) a. 2x^2+2x-8 b. 2x^2+2x+8 c. 2x^2-2x+8 d. -2x^2+2x+8
Weegy: (x^2 – x + 7) + (x^2 + 3x + 1) = b. 2x^2+2x+8 (More)
Question
Expert Answered
Updated 5/31/2014 2:58:24 PM
0 Answers/Comments
Add the following polynomials: (x^2 – x + 7) + (x^2 + 3x + 1) a. 2x^2+2x-8 b. 2x^2+2x+8 c. 2x^2-2x+8 d. -2x^2+2x+8
Weegy: (x^2 - x + 7) + (x^2 + 3x + 1) = 2x^2 + 2x + 8 User: Add the following polynomials: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) a. -5x^2-7x+5 b. 5x^2-7x+5 c. -5x^2+7x+5 d. 5x^2-7x-5 (More)
Question
Updated 8/1/2014 12:52:16 PM
1 Answer/Comment
(–3x^2 + 3x + 3) + (–2x^2 – 10x + 2)
= -5x^2 - 7x + 5
Added 8/1/2014 12:52:16 PM
This answer has been confirmed as correct and helpful.
Add the following polynomials: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) a. -5x^2-7x+5 b. 5x^2-7x+5 c. -5x^2+7x+5 d. 5x^2-7x-5
Weegy: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) = -5x^2 - 7x + 5 (More)
Question
Expert Answered
Updated 8/1/2014 12:50:54 PM
0 Answers/Comments
Add the following polynomials: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) a. -5x^2-7x+5 b. 5x^2-7x+5 c. -5x^2+7x+5 d. 5x^2-7x-5
Weegy: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) = a. -5x^2-7x+5 (More)
Question
Expert Answered
Updated 5/31/2014 2:59:05 PM
0 Answers/Comments
Add the following polynomials: (7x^2 + x + 13) + (2x^2 – 5x + 10) a. -9x^2-4x+23 b. 9x^2+4x+23 c. 9x^2-4x-23 d. 9x^2-4x+23
Weegy: (7x^2 + x + 13) + (2x^2 – 5x + 10) = d. 9x^2-4x+23 (More)
Question
Expert Answered
Updated 5/31/2014 2:59:20 PM
0 Answers/Comments
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