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What is the midpoint of a segment whose endpoints are (-12, 8) and the origin? A) (0, 0) B) (4, 6) C) (-6, 4) D) (6, -4)
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Asked 10/25/2010 4:04:39 PM
Updated 7/27/2014 1:12:11 PM
1 Answer/Comment
Flagged by jerry06 [7/27/2014 1:12:11 PM]
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User: What is the midpoint of a segment whose endpoints are (-12, 8) and the origin? A) (0, 0) B) (4, 6) C) (-6, 4) D) (6, -4)





Question
Asked 10/25/2010 4:04:39 PM
Updated 7/27/2014 1:12:11 PM
1 Answer/Comment
Flagged by jerry06 [7/27/2014 1:12:11 PM]
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The midpoint of a segment whose endpoints are (-12, 8) and the origin is (-6, 4). M = [(-12+0)/2, (8+0)/2]; M = (-12/2, 8/2); M = (-6, 4)
Added 7/27/2014 1:12:08 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/27/2014 1:16:14 PM]
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Questions asked by the same visitor
What is the distance between the points (-19, -4) and (11, 12)? A) 30 B) 34 C) 48 D) 17
Question
Updated 7/14/2014 2:59:26 AM
1 Answer/Comment
The distance between the points (-19, -4) and (11, 12) is 34.
Added 7/14/2014 2:59:26 AM
This answer has been confirmed as correct and helpful.
What is the midpoint of a segment whose endpoints are (4, 0) and (0, -2)? A) (2, -1) B) (4, 2) C) (2, -4) D) (1, -2)
Weegy: (More)
Question
Updated 7/14/2014 2:58:03 AM
3 Answers/Comments
A) (2, -1)
Added 10/25/2010 4:35:57 PM
Added 10/25/2010 4:48:00 PM
The midpoint of a segment whose endpoints are (4, 0) and (0, -2) is (2, -1).

((x1+x2)/2, (y1+y2)/2)
= ((4 + 0)/2, (0 - 2)/2)
= (4/2, -2/2)
= (2, -1)
Added 7/14/2014 2:57:59 AM
This answer has been confirmed as correct and helpful.
What is the midpoint of a segment whose endpoints are (3, 7) and (7, 3)? A) (2, -2) B) (5, -5) C) (2, 2) D) (5, 5)
Weegy: D) (5, 5) If satisfied with the response, please click "Good" (More)
Question
Expert Answered
Updated 7/14/2014 2:56:20 AM
1 Answer/Comment
The \midpoint of a segment whose endpoints are (3, 7) and (7, 3) is (5, 5).

((x1+x2)/2, (y1+y2)/2)

= ((3 + 7)/2, (7 + 3)/2)

= (10/2, 10/2)

= (5, 5)
Added 7/14/2014 2:56:20 AM
This answer has been confirmed as correct and helpful.
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