Multiply these binomials: (–7x – 11)(19x – 14)=

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Asked 1/16/2013 10:45:39 AM

Updated 9/14/2017 4:17:33 PM

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Edited by Masamune [9/14/2017 4:17:33 PM]

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Question

Asked 1/16/2013 10:45:39 AM

Updated 9/14/2017 4:17:33 PM

1 Answer/Comment

Edited by Masamune [9/14/2017 4:17:33 PM]

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(–7x – 11)(19x – 14)

= -133x^2 + 98x - 209x + 154;

= -133x^2 - 111x + 154

= -133x^2 + 98x - 209x + 154;

= -133x^2 - 111x + 154

Added 9/14/2017 2:34:38 PM

This answer has been confirmed as correct and helpful.

Confirmed by Masamune [9/14/2017 4:18:20 PM]

Add the following polynomials: (x^2 – x + 7) + (x^2 + 3x + 1) a. 2x^2+2x-8 b. 2x^2+2x+8 c. 2x^2-2x+8 d. -2x^2+2x+8
**Weegy:** (x^2 – x + 7) + (x^2 + 3x + 1) = b. 2x^2+2x+8 (More)

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Updated 5/31/2014 2:58:24 PM

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a. -9x^2-4x+23
b. 9x^2+4x+23
c. 9x^2-4x-23
d. 9x^2-4x+23
**Weegy:** (7x^2 + x + 13) + (2x^2 – 5x + 10) = d. 9x^2-4x+23 (More)

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Updated 5/31/2014 2:59:20 PM

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Updated 8/1/2014 12:50:54 PM

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Add the following polynomials: (6x^2 – 6x – 6) + (6x^2 – 6x + 9)
a. 12x^2-12x+3
b. 12x^2+12x-3
c. -12x^2-12x+3
d. 12x^2+12x-3
**Weegy:** (6x^2 – 6x – 6) + (6x^2 – 6x + 9) = a. 12x^2-12x+3 (More)

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Asked 1/15/2013 1:50:31 PM

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Add the following polynomials: (3x^2 – 2x – 1) + (2x^2 – 9x + 1)
a. 5x^2+11x
b. -5x^2+11x
c. 5x^2-11x
d. -5x^2-11x

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Updated 2/2/2018 1:35:16 PM

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(3x^2 – 2x – 1) + (2x^2 – 9x + 1) = 5x^2 - 11x

Added 2/2/2018 1:35:16 PM

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