0.8 m³ vessel, methane-air mix at 1 atm.
Adiabatic flame temperature 2200 K.
Determine:
Maximum explosion pressure
Stress in vessel wall
Given: V=0.8 m³, P0=1 atm=101 kPa, T_ad=2200 K, E=210 GPa, r=assume 0.5 m, =12e-6 /°C 1. Maximum explosion pressure (adiabatic, constant volume): P_max = P0*(T_ad/T0) = 101e3*(2200/300) = 740 kPa 2. Wall stress (thin-walled sphere): = P_max*r/(2*t), assume t=0.01 m = 740e3*0.5/(2*0.01) = 18.5 MPa
Question
Asked 15 days ago|2/18/2026 11:27:56 AM
Updated 15 days ago|2/18/2026 12:03:47 PM
3 Answers/Comments