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find the sale price of an item whose original cost is $76 and the rate of discount is 14%
Question
Asked 5/4/2009 9:33:12 PM
Updated 7/11/2015 3:44:45 PM
3 Answers/Comments
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User: multiply 2 3/7 * 3 7/34

User: convert 1.87 grams to mg

User: find the sale price of an item whose original cost is $76 and the rate of discount is 14%

Weegy: $40.55 do you have any other questions?
Expert answered|blizzardxblaine|Points 316|

Question
Asked 5/4/2009 9:33:12 PM
Updated 7/11/2015 3:44:45 PM
3 Answers/Comments
This conversation has been flagged as incorrect.
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8
2 3/7 * 3 7/34
= 17/7 * 109/34
= 1853/238
= 7 187/238
Added 7/11/2015 3:43:48 PM
This answer has been confirmed as correct and helpful.
8
The sale price of an item whose original cost is $76 and the rate of discount is 14% is $65.36.
76(1-.14) = 76*.86 = 65.36
Added 7/11/2015 3:44:45 PM
This answer has been confirmed as correct and helpful.
Comments
Original cost is 76.There is 14% discount.
So
76*14/100=10.64.
So the sale price will be 76-10.64=65.36
Added 5/4/2009 10:44:33 PM
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find the simple interest when the principal is $3200; rate is 4 1/2 % and time is 4 years User: User: find the simple interest when the principal is $9000; rate is 2 % and time is 9 months
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Question
Expert Answered
Updated 7/11/2015 3:40:12 PM
2 Answers/Comments
Simple interest when the principal is $9000; rate is 2 % and time is 9 months is $135.
9000 * .02 * 9/12 = 135
Added 7/11/2015 3:38:54 PM
This answer has been confirmed as correct and helpful.
The bank loans you $6000 at 12% interest for 6 months. The total amount due on the loan is $6,360.

Interest = 6000 * .12 * 1/2 = 360
Total due = 6000 + 360 = 6,360
Added 7/11/2015 3:40:12 PM
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9/16 as a decimal
Question
Updated 6/3/2015 11:41:03 PM
2 Answers/Comments
9/16=0.5625.
As 9 cant be divided by 16,we are placing decimal to get 0 to 9 ie 90.Hence...>.
90/16=5 and rem 10
now 100/16=6 and rem 4.
now 40/16=2 and rem 8
now 80/16=5and rem0.
so .5625 is the answer
Added 5/4/2009 10:41:08 PM

9/16 as decimal is 0.5625
Added 6/3/2015 11:41:03 PM
This answer has been confirmed as correct and helpful.
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