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An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. How far in front of the lens is the image located?
An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. 13.7 millimeters far in front of the lens is the image located. mi/51mm=3.5mm/13mm=13.7 millimeters.
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Asked 2/21/2019 11:37:01 AM
Updated 31 days ago|9/27/2020 12:48:25 PM
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An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. 13.7 millimeters far in front of the lens is the image located.
mi/51mm=3.5mm/13mm=13.7 millimeters.
Added 31 days ago|9/27/2020 12:47:20 PM
This answer has been confirmed as correct and helpful.
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An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. 13.7 millimeters far in front of the lens is the image located.
mi/51mm=3.5mm/13mm=13.7 millimeters.
Added 31 days ago|9/27/2020 12:48:25 PM
This answer has been confirmed as correct and helpful.
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