Which system tool allows you to manage the available space on your hard disk to improve efficiency?
A. Disk Defragmenter
B. ScanDisk
C. DriveSpace
D. Anti-Virus

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Asked 4/7/2014 6:20:47 AM

Updated 4/7/2014 8:02:16 AM

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Question|Asked by masterquece

Asked 4/7/2014 6:20:47 AM

Updated 4/7/2014 8:02:16 AM

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Disk Defragmenter allows you to manage the available space on your hard disk to improve efficiency.

Added 4/7/2014 8:02:16 AM

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To start a program from an icon, you should
A. click the right mouse button.
B. click both mouse buttons at once.
C. double-click the left mouse button.
D. click the left mouse button. **Weegy:** To start a program from an icon, you should double-click the left mouse button .
(More)

Question|Asked by masterquece

Expert Answered

Updated 4/7/2014 7:07:29 AM

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A screen saver is best described as a(n)
A. desktop background pattern or wallpaper.
B. antistatic monitor dust cover.
C. moving full-screen graphic.
D. stationary display, such as a menu or desktop

Question|Asked by masterquece

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Updated 4/7/2014 7:12:35 AM

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A screen saver is best described as a moving full-screen graphic.

Added 4/7/2014 7:12:35 AM

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Find the value of x in the equation 2(x – 3) + 5x = 5(2x + 6).
A. 12 C. 2
B. –12 D. –2 **Weegy:** x**User:** Find the possible values for s in the inequality 12s – 20 50 – 3s – 25.
A. s 3 C. s 5/9
B. s 9 D. s 1/3 (More)

Question|Asked by masterquece

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Updated 4/8/2014 6:54:09 AM

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Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23.
A. r = 12, s = 0 C. r = 4, s = 3
B. r = –12, s = 9 D. r = –1, s = –3

Question|Asked by masterquece

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Updated 4/8/2014 8:04:28 AM

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3r – 4s = 0, multiply 2 on both sides: 6r - 8s = 0 (equation 1)

2r + 5s = 23, multiply 3 on both sides: 6r + 15s = 69 (equation 2)

equation 2 - equation 1 we get: 23s = 69, s= 69/23 = 3

3r - 4(3) = 0, r = 12/3 = 4

The solution for the system of equations 3r – 4s = 0 and 2r + 5s = 23 is C. r = 4, s = 3

2r + 5s = 23, multiply 3 on both sides: 6r + 15s = 69 (equation 2)

equation 2 - equation 1 we get: 23s = 69, s= 69/23 = 3

3r - 4(3) = 0, r = 12/3 = 4

The solution for the system of equations 3r – 4s = 0 and 2r + 5s = 23 is C. r = 4, s = 3

Added 4/8/2014 8:04:28 AM

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Confirmed by jeifunk [4/8/2014 8:05:49 AM]

Find the possible value or values of y in the quadratic equation 4 – 4y – y2 = 0.
A. y = 2 C. y = –3, y = –1
B. y = –4, y = 1 D. y = –2 + 2 2 , y = –2 – 2 2 **Weegy:** 1 **User:** Find the possible value or values of r in the quadratic equation r2 – 7r – 8 = 0. (More)

Question|Asked by masterquece

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Updated 4/8/2014 7:43:28 AM

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