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Solve the system algebraically. 4x - 5y = 3 x = 3 - 1/2y What is the value of x? 9/7 24/14 33/14
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Asked 9/28/2014 5:06:48 PM
Updated 9/29/2014 6:36:23 AM
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User: Solve the system algebraically. 4x - 5y = 3 x = 3 - 1/2y What is the value of x? 9/7 24/14 33/14

Weegy: 9/7
ki|Points 96|

Question
Asked 9/28/2014 5:06:48 PM
Updated 9/29/2014 6:36:23 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [9/29/2014 6:36:22 AM]
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4x - 5y = 3, x = 3 - 1/2y;

Multiply (x + 1/2y = 3) by -4:
-4x - 2y = -12;
Add two equation:
(4x - 5y = 3) + (-4x - 2y = -12):
-7y = -9;
y = 9/7;
Solve for x:
4x - 5y = 3;
4x - 5(9/7) = 3;
4x - 45/7 = 3;
4x = 3 + 45/7;
4x = 66/7;
x = (66/7)/(4);
x = 66/28 = 33/14

Solutions: x = 33/14, y = 9/7.
The value of x is 33/14.
Added 9/29/2014 6:36:23 AM
This answer has been confirmed as correct and helpful.
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Solve this system algebraically. 9x + 2y = 5 y - 2x + 3 = 0
Weegy: The solution for 2x+y-10=0, x - y - 4 = 0 is x = 14/3 ,y = 2/3. From 2x + y - 10 = 0 ,we can get y = 10-2x put y= 10 - 2x into the 2th equation x - y - 4 = 0 x -(10 -2x) - 4 = 0 3x = 14 x =14/3 y= 10 -2x y= 10 - 2*14/3 y= 2/3 (More)
Question
Updated 9/29/2014 4:05:14 AM
1 Answer/Comment
The solutions for 9x + 2y = 5, y - 2x + 3 = 0 are x = 11/13, y = -17/13

Multiply -2x + y = -3 by -2:
4x - 2y = 6;
Add two equations:
(9x + 2y = 5) + (4x - 2y = 6):
13x = 11; x = 11/13;
Solve for y:
9x + 2y = 5;
9(11/13) + 2y = 5;
99/13 + 2y = 5;
2y = 5 - 99/13;
2y = -34/13;
y = (-34/13)/2;
y = -34/26 = -17/13
Added 9/29/2014 4:05:12 AM
This answer has been confirmed as correct and helpful.
Listening has different purposes. True False
Weegy: Listening has different purposes. TRUE. (More)
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Expert Answered
Updated 9/28/2014 1:11:07 PM
0 Answers/Comments
Solve this system algebraically. 7x - 2y = 4 5y + 3x = 10
Weegy: i am sorry but is not working to copy and paste all signs so please follow the link and you will see the entire solution, thank you (More)
Question
Updated 9/28/2014 3:37:08 PM
1 Answer/Comment
The solutions for the system 7x - 2y = 4, 5y + 3x = 10 are x = 40/41, y = 58/41
(7x - 2y = 4) * 5:
35x - 10y = 20;
(3x + 5y = 10) * 2:
6x + 10y = 20;
(35x - 10y = 20) + (6x + 10y = 20):
41x = 40;
x = 40/41;
Solve for y:
7x - 2y = 4;
7(40/41) - 2y = 4;
280/41 - 2y = 4;
-2y = 4 - 280/41;
-2y = -116/41;
y = (-116/41)/(-2);
y = 116/82 = 58/41
Added 9/28/2014 3:36:58 PM
This answer has been confirmed as correct and helpful.
What is the result of adding the system of equations? 2x + y = 4 3x - y = 6 x = 2 x = 10 5x = 10
Weegy: The result of adding the system of equations 2x + y = 4, 3x - y = 6 is 5x = 10. (More)
Question
Updated 9/28/2014 3:12:12 PM
0 Answers/Comments
Solve the system algebraically. Check your work. 5x + 2y = 10, 3x + 2y = 6
Weegy: 5x + 2y = 10, 3x + 2y = 6; Multiply 5x + 2y = 10 by 3: 15x + 6y = 30 Multiply 3x + 2y = 6 by 5: 15x + 10y = 30 Subtract: (15x + 10y = 30) - (15x + 6y = 30): 4y = 0 Solve for y: 4y = 0, y = 0/4 = 0 Solve for x using y = 0: 5x + 2y = 10 5x + 2(0) = 10 5x = 10 x = 10/5 x = 2 The solutions for the systems 5x + 2y = 10, 3x + 2y = 6 is x = 2, y = 0. CHECK: 5x + 2y = 10 5(2) + 0 = 10 10 = 10 3x + 2y = 6 3(2) + 0 = 6 6 = 6 (More)
Question
Updated 9/29/2014 6:42:07 AM
0 Answers/Comments
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