Which of the following is true regarding the properties of light? A. Light has a dual nature and acts like both a wave and a particle. B. Light can travel only in a straight line. C. Light needs a medium to propagate through a vacuum. D. Light doesn't display interference or diffraction.
Question
Updated 9/29/2021 1:57:46 PM
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Original conversation
User: Which of the following is true regarding the properties of light? A. Light has a dual nature and acts like both a wave and a particle. B. Light can travel only in a straight line. C. Light needs a medium to propagate through a vacuum. D. Light doesn't display interference or diffraction.

Weegy: Light has a dual nature and acts like both a wave and a particle is true regarding the properties of light.
|Score .9663|sujaysen|Points 25715|

User: A wave with a period of 1 3 second has a frequency of A. 67 Hz. B. 33 Hz. C. 300 Hz. D. 3 Hz.

Weegy: A wave with a period of 1 3 second has a frequency of 3 Hz.
|Score 1|destle6|Points 14797|

User: A wave with a period of 0.008 seconds has a frequency of A. 80 Hz. B. 12.5 Hz. C. 800 Hz. D. 125 Hz.

Weegy: A wave with a period of 0.008 second has a frequency of: 125 Hz.
|Score 1|yumdrea|Points 47336|

User: If a source of sound waves is rapidly approaching a person, the sound heard by the person appears to have A. a period higher than the original period. B. a frequency higher than the original frequency. C. a pitch lower than the original pitch. D. an amplitude lower than the original amplitude.

Weegy: If a source of sound waves is rapidly approaching a person, the sound heard by the person appears to have: a frequency higher than the original frequency.
|Score 1|sharpies|Points 8768|

User: You increase the temperature from 30°C to 36°C. What's the velocity of the sound wave at this new temperature? A. 350.0 Hz B. 335.6 Hz C. 352.6 Hz D. 344.0 Hz

Question
Updated 9/29/2021 1:57:46 PM
Rating
3
Your boss asks you to adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30 degrees to 36 degrees. Velocity of sound in air = 331.5 m/s + 0.59 m/s*°C times (the new temperature) v = 331.5 + 0.59 * 36 v= 352.6 Hz.

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Weegy: Acceleration is expressed in meters per second squared. (More)
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In a practical machine, the power output is less than the power input. Considering the law of energy conservation, what can explain this occurrence? A. Some of the energy coming out of the machine is being destroyed. B. Some of the energy going into the machine is being created at a quicker rate than the energy coming out is being destroyed. C. Some of the energy is used to combat friction and thus is transformed from mechanical energy to heat. D. Some of the energy going into the ...
Question
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In a practical machine, the power output is less than the power input. Some of the energy is used to combat friction and thus is transformed from mechanical energy to heat can explain this occurrence.
If a tank filled with water contains a block, and the height of the water above point A within the block is 0.6 meters, what's the pressure at point A?
Question
Updated 4/11/2021 11:19:00 PM
If a tank filled with water contains a block and the height of the water above point A within the block is 0.6 meter, the pressure at point is 5.88kPa

p= 1000 kg/m3*9.8 m/s2*0.6m = 5.88kPa.
Your boss asks you to adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to 36°C. What's the velocity of the sound wave at this new temperature? A. 350.0 Hz B. 335.6 Hz C. 352.6 Hz D. 344.0 Hz
Question
Updated 10/2/2021 3:48:24 PM
Your boss asks you to adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30 degrees to 36 degrees. Velocity of sound in air = 331.5 m/s + 0.59 m/s*°C times (the new temperature) v = 331.5 + 0.59 * 36 v= 352.6 Hz.
What's the velocity of the sound wave at 36 C
Question
Updated 1/15/2023 7:38:50 PM
You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30 C to 36 C. The velocity of the sound wave at this new temperature is 352.6 m/s. Solution: v = 331 + 0.6T, where v is the velocity of the sound wave in units of m/s and T is the temperature measured in degrees Celsius. When the temperature is 36°C, the velocity of the sound wave is: v = 331 + (0.6)(36) = 331 + 21.6 = 352.6 m/s.
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