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The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is (x - 4) y = 2v3 (x - 4) y = 12 (x 4) y = 12
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Asked 2/5/2013 8:10:32 AM
Updated 7/8/2014 9:46:59 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/8/2014 9:45:45 AM]
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User: The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is (x - 4) y = 2v3 (x - 4) y = 12 (x 4) y = 12

Weegy: 3-3 = 0
andrewpallarca|Points 19118|

User: (x + 3)² + (y - 5)² = 25

Weegy: 3-3 = 0
andrewpallarca|Points 19118|

Question
Asked 2/5/2013 8:10:32 AM
Updated 7/8/2014 9:46:59 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/8/2014 9:45:45 AM]
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The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is (x - 4)^2 + y^2 = 12.
Added 7/8/2014 9:46:10 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/8/2014 9:48:42 AM]
3
(x + 3)² + (y - 5)² = 25 is a circle equation with center (-3, 5), radius = 5.
Added 7/8/2014 9:46:59 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/8/2014 9:48:43 AM]
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