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In a pulley system, a 5-newton weight is to be lifted 2 meters. The rope is pulled 10 meters. The effort force is two newtons. IMA = AMA = efficiency = % .
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Asked 6/10/2009 2:10:57 PM
Updated 244 days ago|6/30/2023 10:51:28 AM
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User: In a pulley system, a 5-newton weight is to be lifted 2 meters. The rope is pulled 10 meters. The effort force is two newtons. IMA = AMA = efficiency = % .

Weegy: IMA is a multiplier. Meaning it represents how much the machine will multiply the force which is put into it. It, therefore, has no unit and would be written like: 3. [ [ [ This means that whatever amount of work is put into the machine, you will get 3 times the work out. Effort will usually be a distance: cm, m Resistance will also usually be a distance although it needs to be the same unit as the effort so we compare apples to apples. :) ] ] ]
Expert answered|weegyexpert|Points 290|

User: In a pulley system, a 5-newton weight is to be lifted 2 meters. The rope is pulled 10 meters. The effort force is two newtons. IMA = AMA = efficiency = %

Question
Asked 6/10/2009 2:10:57 PM
Updated 244 days ago|6/30/2023 10:51:28 AM
1 Answer/Comment
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3

To calculate the IMA (Ideal Mechanical Advantage) of a pulley system, we can use the formula:

IMA = (Distance the effort force moves) / (Distance the load moves)

In this case, the distance the effort force moves is 10 meters (as mentioned in the question), and the distance the load moves is 2 meters. Therefore, the IMA can be calculated as:

IMA = 10 / 2 = 5

The IMA represents the theoretical advantage of the pulley system.

The AMA (Actual Mechanical Advantage) of a pulley system takes into account factors such as friction and other losses. In an ideal pulley system without any losses, the AMA would be equal to the IMA. So, in this case, the AMA is also 5.

Efficiency is defined as the ratio of output work to input work, expressed as a percentage. In a pulley system, the output work is the work done on the load (weight lifted), and the input work is the work done by the effort force. Since the effort force is two newtons and the load is five newtons, the efficiency can be calculated as:

Efficiency = (Output work / Input work) * 100
= (5 / 2) * 100
= 250%

Therefore, the efficiency of the pulley system is 250%.
Added 244 days ago|6/30/2023 10:51:28 AM
This answer has been confirmed as correct and helpful.
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