multiply... (4x+4)(6x^2 +8x+3)

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Asked 3/20/2012 9:32:07 AM

Updated 3/21/2012 11:26:01 AM

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User: multiply... (4x+4)(6x^2 +8x+3)

Weegy: a. Factor as: (x - 3)(x + 1)^3 = 0 zeros are at x = 3 and x = -1 y ' = 4x^3 - 12x - 8 4(x - 2)(x + 1)^2 zeros at x = 2 and x = -1 - - - - - - - - - - - - - - - - - - - - b. y " = 12x^2 - 12 y "(2) = 36 which is positive, [ so x = 2 is a minimum point y "(-1) = 0, an inflection point - - - - - - - - - - - - - - - - - - - - c. f(x) decreases from [-8, 2] and increases from [2, +8] - - - - - - - - - - - - - - - - - - - - d. f(x) is negative for x = [-1, 3] and positive for all other real values ]
Expert answered|LeighaI|Points 0|

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Asked 3/20/2012 9:32:07 AM

Updated 3/21/2012 11:26:01 AM

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AngelInDisguise

(4x+4)(6x^2 +8x+3) = 24x^3 + 56x^2 + 44x + 12

Added 3/20/2012 10:42:09 AM

This answer has been confirmed as correct and helpful.

Unflagged by andrewpallarca [7/7/2014 7:25:01 PM], Confirmed by andrewpallarca [7/7/2014 7:25:03 PM]

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solve for v.... 6/v=9/v-1/2

Weegy: The answer is v = 4. :) User: solve for b.... b^2 - 6b - 7=0 (More)

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Expert Answered

Updated 9/20/2014 10:57:20 PM

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janezeshun

6/v=9/v-1/2
6/v - 9/v = -1/2
-3/v = -1/2
v = -3/( -1/2)
v= -3 *(-2)
v = 6

Added 9/20/2014 10:56:18 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [9/20/2014 11:00:45 PM]

janezeshun

b^2 - 6b - 7=0
(b - 7)(b + 1) = 0
b = 7 or b = -1.

Added 9/20/2014 10:57:20 PM

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