The perimeter of a triangle is 7a - 11b. If two of its sides are 2a + b and a - 9b, what is the third side?
Question
Updated 2/3/2015 4:34:15 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [2/3/2015 4:32:30 AM]
Original conversation
User: Subtract 2x2 - 6x - 4 from 4x2 - 4x + 3.

User: The perimeter of a triangle is 7a - 11b. If two of its sides are 2a + b and a - 9b, what is the third side?

Weegy: The perimeter of a triangle is 7a - 11b. If two of its sides are 2a + b and a - 9b, what is the third side? side03 = (7a-11b) - {(2a+b) + (a-9b)} = 7a - 11b - 2a - b - a + 9b = (7-2-1)a +(-11-1+9)b = 4a - 2b ............................ answer
itstud|Points 170|

User: What must be added to 3x -7 to make x2 + 4x -1?

Weegy: X2+1x+6 must be added to 3x-7
ArslanBasit|Points 1965|

User: x4 -3x + 1, 4x2 - 2x + 8, and x3 - 9

Weegy: Answer is 6x+7 12 + 3(2x - 3) + 4 12+6x-9+4 12+6x-5 6x+7
borninboston777|Points 80|

User: By how much does a3 - 2a exceed a2 + a - 6?

Weegy: 3-3 = 0
andrewpallarca|Points 21459|

Question
Updated 2/3/2015 4:34:15 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [2/3/2015 4:32:30 AM]
Rating
3
4x^2 - 4x + 3 - (2x^2 - 6x - 4)
= 4x^2 - 2x^2 - 4x + 6x + 3 + 4
= 2x^2 + 2x + 7
Confirmed by yumdrea [2/3/2015 1:41:32 PM]
3
x^4 - 3x + 1 + (4x^2 - 2x + 8) + (x^3 - 9)
= x^4 + x^3 + 4x^2 - 3x - 2x + 1 + 8 - 9
= x^4 + x^3 + 4x^2 - 5x
Confirmed by yumdrea [2/3/2015 1:42:59 PM]

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