If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point (5, 6).
Question
Updated 7/3/2014 1:50:13 AM
Flagged by yeswey [7/3/2014 1:50:00 AM]
Original conversation
User: If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point (5, 6).

Question
Updated 7/3/2014 1:50:13 AM
Flagged by yeswey [7/3/2014 1:50:00 AM]
Rating
3
If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, it passes through point (5, 6). FALSE.

Confirmed by jeifunk [7/3/2014 1:57:21 AM]

Questions asked by the same visitor
hat is the equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3)? 5x- 6y- 8 = 0 3y= -2x + 20 y=x-
Question
Updated 8/5/2014 12:23:55 AM
The equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3) is y = 5/6x - 4/3
Confirmed by jeifunk [8/5/2014 3:01:50 AM]
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