Solve this quadratic equation.
x2 + 5x + 3 = 0

Question

Asked 4/29/2011 2:12:14 PM

Updated 7/17/2014 4:56:59 AM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by andrewpallarca [7/17/2014 4:53:09 AM]

f
freestar.config.enabled_slots.push({ placementName: 'weegy_incontent_1', slotId: 'weegy_incontent_1' });

mchlklck|Points 2172|

ihcvin|Points 185|

fireandh20|Points 1550|

Question

Asked 4/29/2011 2:12:14 PM

Updated 7/17/2014 4:56:59 AM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by andrewpallarca [7/17/2014 4:53:09 AM]

Rating

8

7x^2 + 3x = 0;

x(7x + 3) = 0;

x = 0 or 7x + 3 = 0; 7x = -3; x = -3/7

Solution set is {0, -3/7}

x(7x + 3) = 0;

x = 0 or 7x + 3 = 0; 7x = -3; x = -3/7

Solution set is {0, -3/7}

Added 7/17/2014 4:53:07 AM

This answer has been confirmed as correct and helpful.

8

(x - 2)(x - 3) = 2;

x^2 - 5x + 6 = 2;

x^2 - 5x + 6 - 2 = 0;

x^2 - 5x + 4 = 0;

(x - 1)(x - 4) = 0;

(x - 1) = 0; x = 1 or (x - 4) = 0; x = 4

the solution set is (x = 1, x = 4)

x^2 - 5x + 6 = 2;

x^2 - 5x + 6 - 2 = 0;

x^2 - 5x + 4 = 0;

(x - 1)(x - 4) = 0;

(x - 1) = 0; x = 1 or (x - 4) = 0; x = 4

the solution set is (x = 1, x = 4)

Added 7/17/2014 4:56:59 AM

This answer has been confirmed as correct and helpful.

36,686,965

questions answered

There are no comments.