Working with polynomial: (12y³ + 8 y² + 20y) / 2y

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Asked 12/12/2010 1:34:01 PM

Updated 7/16/2014 11:09:47 AM

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Expert answered|selymi|Points 5|

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Asked 12/12/2010 1:34:01 PM

Updated 7/16/2014 11:09:47 AM

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(12y³ + 8y² + 20y) / (2y)

= (12y³/2y) + (8y²/2y) + (20y/2y)

= 6y^2 + 4y + 10

= (12y³/2y) + (8y²/2y) + (20y/2y)

= 6y^2 + 4y + 10

Added 7/16/2014 11:09:46 AM

This answer has been confirmed as correct and helpful.

Working with polynomial: (8x – 5) + (7x + 4) **Weegy:**
(8x – 5) + (7x + 4)
= 8x + 7x - 5 + 4
= 15x - 1
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Updated 6/23/2020 6:24:21 AM

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Working with polynomial: (5x – 3.6) – (4x + 1.2)

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Updated 7/3/2014 1:57:21 PM

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Working with polynomial: (3x^2 + 3x) + (4x + 4). Please show the steps on how you got your answer. Thanks!

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Updated 8/10/2014 5:55:48 PM

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(3x^2 + 3x) + (4x + 4)

= 3x^2 + 3x + 4x + 4;

= 3x^2 + 7x + 4

= 3x^2 + 3x + 4x + 4;

= 3x^2 + 7x + 4

Added 8/10/2014 5:55:48 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/10/2014 5:57:18 PM]

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