Question and answer
Working with polynomial: (12y³ + 8 y² + 20y) / 2y
Question|Rated bad
Asked 12/12/2010 1:34:01 PM
Updated 7/16/2014 11:09:47 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [7/16/2014 11:09:47 AM]
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User: Working with polynomial: (12y³ + 8 y² + 20y) / 2y

Weegy: x+2y+z --> x = -2y-z
Expert answered|selymi|Points 5|

Question|Rated bad
Asked 12/12/2010 1:34:01 PM
Updated 7/16/2014 11:09:47 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [7/16/2014 11:09:47 AM]
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(12y³ + 8y² + 20y) / (2y)
= (12y³/2y) + (8y²/2y) + (20y/2y)
= 6y^2 + 4y + 10
Added 7/16/2014 11:09:46 AM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
Simplify (-4xy^5) (-5x^4y^3)
Weegy: (-4xy^5) (-5x^4y^3) = 20x^5y^8 (More)
Question
Expert Answered
Updated 5/12/2015 2:49:09 PM
0 Answers/Comments
Okay here is another one: Simplify (9x²y4)³
Question
Updated 2/25/2014 1:38:11 AM
1 Answer/Comment
(9x^2y^4)^3 is 729 x^6 y^12.
Added 2/25/2014 1:38:11 AM
This answer has been confirmed as correct and helpful.
Please Simplify (9x²y4)³. Thanks!
Question
Updated 1/28/2014 11:48:45 AM
1 Answer/Comment
(9x²y4)³

= 729x^6y^12
Added 1/28/2014 11:48:45 AM
This answer has been confirmed as correct and helpful.
(-3xy²)(-7x²y^4)
Weegy: (-3xy²)(-7x²y^4) = 21x^3y^6 (More)
Question
Expert Answered
Updated 9/11/2014 11:21:20 AM
2 Answers/Comments
(-3xy^²)(-7x^²y^4)

=21x^3y^6
Added 9/11/2014 8:15:41 AM
This answer has been flagged as incorrect.
Flagged by andrewpallarca [9/11/2014 11:19:13 AM]
janezeshun, please make sure to check the whole conversation if there is a correct answer already to avoid posting a duplicate one. The expert was able to answer the question correctly, and this conversation needed to be edited to remove some contents that do not add value.
Added 9/11/2014 11:21:20 AM
Working with polynomial: (8x – 5) + (7x + 4)
Weegy: (8x – 5) + (7x + 4) = 8x + 7x - 5 + 4 = 15x - 1 (More)
Question
Expert Answered
Updated 6/23/2020 6:24:21 AM
0 Answers/Comments
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