Airplane flies 300 km at 100 m/s, then 200 km at 50 m/s. Find average speed

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Distance1 = 300 km = 300000 m, v1 = 100 m/s Time1 = 300000 / 100 = 3000 s Distance2 = 200 km = 200000 m, v2 = 50 m/s Time2 = 200000 / 50 = 4000 s Total distance = 500 km = 500000 m Total time = 3000 + 4000 = 7000 s Average speed = Total distance / Total time = 500000 / 7000 = 71.43 m/s

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Asked 41 days ago|3/2/2026 9:29:01 AM

Updated 41 days ago|3/2/2026 10:11:30 AM

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cruz30

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Added 41 days ago|3/2/2026 10:11:22 AM

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cruz30

Distance1 = 300 km = 300000 m, v1 = 100 m/s
Time1 = 300000 / 100 = 3000 s
Distance2 = 200 km = 200000 m, v2 = 50 m/s
Time2 = 200000 / 50 = 4000 s
Total distance = 500 km = 500000 m
Total time = 3000 + 4000 = 7000 s
Average speed = Total distance / Total time = 500000 / 7000 = 71.43 m/s

Added 41 days ago|3/2/2026 10:11:30 AM

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Added 41 days ago|3/2/2026 7:09:45 AM

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Added 41 days ago|3/2/2026 7:08:21 AM

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Added 41 days ago|3/2/2026 7:13:23 AM

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Updated 41 days ago|3/2/2026 7:12:07 AM

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cruz30

Distance = 150 km, Speed1 = 40, Speed2 = 50
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Added 41 days ago|3/2/2026 7:11:32 AM

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Salas1987

Time = 150 km / 90 km/h = 1.666... hours.

To express this in hours and minutes, 1.666... hours is 1 hour and (0.666... * 60) minutes, which is approximately 1 hour and 40 minutes.
Therefore, the trains will meet in approximately 1 hour and 40 minutes.

Added 41 days ago|3/2/2026 7:12:07 AM

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