Use the quadratic formula to solve 4y2 + 8y + 7 = 4.

4y^2 + 8y + 7 = 4 4y^2 + 8y + 7 - 4 = 0 4y^2 + 8y + 3 = 0 a = 4, b = 8, c = 3 b^2 - 4ac = 8^2 - 4(4)(3) = 64 - 48 = 16 x = (-8 ± sqrt 16)/8 = (-8 ± 4)/8 x = -1/2 or x = -3/2

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Asked 6/7/2013 5:06:12 PM

Updated 6/6/2014 12:03:08 AM

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Edited by andrewpallarca [6/6/2014 10:44:44 AM]

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4y^2 + 8y + 7 = 4

4y^2 + 8y + 7 - 4 = 0

4y^2 + 8y + 3 = 0

a = 4, b = 8, c = 3

b^2 - 4ac = 8^2 - 4(4)(3) = 64 - 48 = 16

x = (-8 ± sqrt 16)/8

= (-8 ± 4)/8

x = -1/2 or x = -3/2

4y^2 + 8y + 7 - 4 = 0

4y^2 + 8y + 3 = 0

a = 4, b = 8, c = 3

b^2 - 4ac = 8^2 - 4(4)(3) = 64 - 48 = 16

x = (-8 ± sqrt 16)/8

= (-8 ± 4)/8

x = -1/2 or x = -3/2

Added 6/6/2014 12:03:08 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/6/2014 10:44:45 AM]

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