Question and answer
Jack cut a piece of wood that was 8 feet long into two pieces. One piece is three times as long as the other. How long is the shorter piece of wood? A. 2 feet long C. 1 foot long B. 4 feet long D. 3 feet long
Let x be the length of the shorter piece of wood, then the length of the longer piece is 3x; given x + 3x = 8, solve the equation x = 2. The length of the shorter piece of wood is A. 2 feet long.
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Question|Asked by masterquece
Asked 4/8/2014 5:29:11 AM
Updated 4/8/2014 6:28:13 AM
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Let x be the length of the shorter piece of wood, then the length of the longer piece is 3x; given x + 3x = 8, solve the equation x = 2.
The length of the shorter piece of wood is A. 2 feet long.
Added 4/8/2014 6:28:13 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/8/2014 6:31:51 AM]
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Disk Defragmenter allows you to manage the available space on your hard disk to improve efficiency.
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A screen saver is best described as a(n) A. desktop background pattern or wallpaper. B. antistatic monitor dust cover. C. moving full-screen graphic. D. stationary display, such as a menu or desktop
Question|Asked by masterquece
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Updated 4/7/2014 7:12:35 AM
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A screen saver is best described as a moving full-screen graphic.
Added 4/7/2014 7:12:35 AM
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Find the value of x in the equation 2(x – 3) + 5x = 5(2x + 6). A. 12 C. 2 B. –12 D. –2
Weegy: xUser: Find the possible values for s in the inequality 12s – 20 50 – 3s – 25. A. s 3 C. s 5/9 B. s 9 D. s 1/3 (More)
Question|Asked by masterquece
Not Answered
Updated 4/8/2014 6:54:09 AM
1 Answer/Comment
2(x – 3) + 5x = 5(2x + 6)
2x - 6 + 5x = 10x + 30
7x - 6 = 10x + 30
7x - 10x = 30 + 6
-3x = 36
x = -12
Added 4/8/2014 6:54:09 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/8/2014 7:06:32 AM]
Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23. A. r = 12, s = 0 C. r = 4, s = 3 B. r = –12, s = 9 D. r = –1, s = –3
Question|Asked by masterquece
Updated 4/8/2014 8:04:28 AM
1 Answer/Comment
3r – 4s = 0, multiply 2 on both sides: 6r - 8s = 0 (equation 1)
2r + 5s = 23, multiply 3 on both sides: 6r + 15s = 69 (equation 2)
equation 2 - equation 1 we get: 23s = 69, s= 69/23 = 3
3r - 4(3) = 0, r = 12/3 = 4
The solution for the system of equations 3r – 4s = 0 and 2r + 5s = 23 is C. r = 4, s = 3
Added 4/8/2014 8:04:28 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/8/2014 8:05:49 AM]
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