Question and answer
pq - 3r + pr - 3q.
Question
Asked 6/10/2013 10:24:57 AM
Updated 7/17/2014 3:23:06 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by jerry06 [7/17/2014 3:23:06 PM]
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Original conversation
User: pq - 3r + pr - 3q.

Weegy: The expression 3r - 6 can be written as r - 2.
may100|Points 2426|

User: Factor the four-term polynomial. pq - 3r + pr - 3q.

Weegy: The expression 3r - 6 can be written as r - 2.
may100|Points 2426|

User: pq - 3r + pr - 3q.

Weegy: The expression 3r - 6 can be written as r - 2.
may100|Points 2426|

User: pq - 3r + pr - 3q.

Weegy: The expression 3r - 6 can be written as r - 2.
may100|Points 2426|

Question
Asked 6/10/2013 10:24:57 AM
Updated 7/17/2014 3:23:06 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by jerry06 [7/17/2014 3:23:06 PM]
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8
pq - 3r + pr - 3q = (p - 3)(q + r)
Added 7/17/2014 3:23:04 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/19/2014 9:25:08 AM]
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Questions asked by the same visitor
Find the product of (5a - 7)(2a - 1)?
Question
Updated 1/28/2018 7:24:33 AM
1 Answer/Comment
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
Question
Updated 7/3/2014 8:38:35 PM
1 Answer/Comment
The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Added 7/3/2014 8:38:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Not Answered
Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
Write the equation of the given circle. center (1, -5) radius of 10
Question
Not Answered
Updated 7/3/2014 8:34:36 PM
1 Answer/Comment
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Added 7/3/2014 8:34:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
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