Evaluate 5! + 2!.

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Asked 9/12/2014 10:56:27 AM

Updated 9/12/2014 11:36:08 AM

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Question

Asked 9/12/2014 10:56:27 AM

Updated 9/12/2014 11:36:08 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by andrewpallarca [9/12/2014 11:36:08 AM]

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5! + 2!

= (1 * 2 * 3 * 4 * 5) + (1 * 2)

= 120 + 2

= 122

= (1 * 2 * 3 * 4 * 5) + (1 * 2)

= 120 + 2

= 122

Added 9/12/2014 11:36:07 AM

This answer has been confirmed as correct and helpful.

x(x2 + 1) = 0 is this quadratic **Weegy:** x= -2
(-2)2+4=0
-4+4=0
0=0 **User:** 5(4x + 2) = 3 is this quadratic **Weegy:** The equation (x + 3)(x + 4) = 5 is quadratic. **User:** (x + 3)(x + 4) = 5 is this quadratic **Weegy:** Here is a website which give you some examples
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Updated 9/14/2014 9:34:34 PM

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x(x^2 + 1) = 0 This is not quadratic.

Added 9/14/2014 9:32:25 PM

This answer has been confirmed as correct and helpful.

5(4x + 2) = 3 This is not quadratic.

Added 9/14/2014 9:33:09 PM

This answer has been confirmed as correct and helpful.

(x + 3)(x + 4) = 5 This is quadratic.

(x + 3)(x + 4) = 5

x^2 + 7x + 12 - 5 = 0

x^2 + 7x + 7 = 0 which is quadratic.

(x + 3)(x + 4) = 5

x^2 + 7x + 12 - 5 = 0

x^2 + 7x + 7 = 0 which is quadratic.

Added 9/14/2014 9:34:34 PM

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y(y + 4) - y = 6 is a quadratic equation **Weegy:** y(y + 4) - y^2 = 6 y^2 + 4y - y^2 = 0 4y = 0, y= 0 whose gragh is y axle. Thus, y(y + 4) - y^2 = 6 is a quadratic equation. This is false. (More)

Question

Updated 9/14/2014 9:27:30 PM

1 Answer/Comment

y(y + 4) - y = 6 is a quadratic equation. TRUE.

y(y + 4) - y = 6

y^2 + 4y - y = 6

y^2 + 3y - 6 = 0 which is quadratic equation.

y(y + 4) - y = 6

y^2 + 4y - y = 6

y^2 + 3y - 6 = 0 which is quadratic equation.

Added 9/14/2014 9:27:30 PM

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The hypotenuse of a right triangle is 25 cm, and the shorter leg is 15 cm. Find the length of the other leg.

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Updated 9/16/2014 1:28:20 PM

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The hypotenuse of a right triangle is 25 cm, and the shorter leg is 15 cm. The length of the other leg is 20 cm. b = sqrt [(25)^2 - (15)^2]; b = sqrt (625 - 225); b = sqrt 400; b = 20

Added 9/16/2014 1:28:20 PM

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Determine the solution set of (x + 1)2 = 25

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Updated 9/16/2014 11:53:35 AM

1 Answer/Comment

The solution set of (x + 1)^2 = 25 is x = -6, x = 4

(x + 1)^2 = 25;

x^2 + x + x + 1 = 25;

x^2 + 2x + 1 = 25;

x^2 + 2x + 1 - 25 = 0;

x^2 + 2x - 24 = 0;

(x + 6)(x - 4) = 0;

x + 6 = 0; x = -6;

x - 4 = 0; x = 4

(x + 1)^2 = 25;

x^2 + x + x + 1 = 25;

x^2 + 2x + 1 = 25;

x^2 + 2x + 1 - 25 = 0;

x^2 + 2x - 24 = 0;

(x + 6)(x - 4) = 0;

x + 6 = 0; x = -6;

x - 4 = 0; x = 4

Added 9/16/2014 11:53:35 AM

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