solve for x: 6x^2 -9x + 1=0
Question
Updated 6/3/2014 3:06:38 AM
Flagged by yeswey [6/3/2014 3:06:38 AM]
Original conversation
User: solve for x: 6x^2 -9x + 1=0

Question
Updated 6/3/2014 3:06:38 AM
Flagged by yeswey [6/3/2014 3:06:38 AM]
Rating
3
6x^2 - 9x + 1 = 0
b^2 - 4ac = (-9)^2 - 4(6)(1) = 81 - 24 = 57
x = [-b ± sqrt (b^2 - 4ac)]/2a
= (9 ± sqrt 57)/12
Confirmed by andrewpallarca [6/3/2014 2:34:21 PM]

Questions asked by the same visitor
compute the value of the discriminant and give the number of real solutions of the quadratic equation: -8x^2 + 3x + 2=0
Question
Updated 7/27/2014 3:41:31 PM
-8x^2 + 3x + 2=0
Discriminant:
b^2 - 4ac
= (3)^2 - 4(-8)(2)
= 9 + 64
= 73, two irrational solutions.
27,350,105
*
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