Find the product. If the result is negative, enter "-". If the result is positive, leave the box empty.
-7(-a^2)^2(-b^3)

s

Question

Asked 7/25/2016 4:59:04 PM

Updated 7/25/2016 10:53:25 PM

1 Answer/Comment

Deleted by jeifunk [7/25/2016 9:45:19 PM], Undeleted by jeifunk [7/25/2016 9:45:20 PM], Flagged by jeifunk [7/25/2016 9:45:20 PM]

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-7(-a^2)^2(-b^3)

= -7a^4(-b^3)

= 7a^4b^3

= -7a^4(-b^3)

= 7a^4b^3

Added 7/25/2016 10:53:25 PM

This answer has been confirmed as correct and helpful.

Which of the following is the solution set of -2|x| **Weegy:** The solution set of -2|x| 4}. -2|x| -8/-2 |x| > 4 x > 4 or x < -4 (More)

Question

Updated 7/23/2016 7:22:57 PM

0 Answers/Comments

Find the quotient.
48j^5 k^2 (-3j^3 k)

Question

Updated 7/25/2016 7:59:32 PM

1 Answer/Comment

48j^5 k^2 / (-3j^3k)

= - 48j2k/3

= - 16j2k

= - 48j2k/3

= - 16j2k

Added 7/25/2016 7:59:32 PM

This answer has been confirmed as correct and helpful.

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Question

Updated 7/25/2016 8:07:26 PM

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Simplify m - {n - [p (m n - p)]}.
**Weegy:** {n - 1 - [n - 1 - (n - 1)]} = (n - n + n)+( - 1 + 1 - 1) = n - 1 (More)

Question

Updated 7/25/2016 8:11:05 PM

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