If a number is divisible by both 2 and 3 then we can say the number is divisible by?
A. 2.
B. 5.
C. 6.
D. 4.

If a number is divisible by both 2 and 3 then we can say the number is divisible by 6.

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Question

Asked 10/14/2018 9:35:27 AM

Updated 10/14/2018 1:01:52 PM

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If a number is divisible by both 2 and 3 then we can say the number is divisible by
A. 2.
B. 5.
C. 6.
D. 4. **Weegy:** If a number is divisible by both 2 and 3 then we can say the number is divisible by 6. **User:** Solve for x in the equation x/2 = 17.
A. x = 8.5
B. x = 34
C. x = 15
D. x = 19 **Weegy:** x/2 = 17; x = 17 * 2; x = 34. **User:** Which of the following is a multiple of 2?
A. 1,000
B. 75
C. 2,461
D. 847 **Weegy:** 1,000 is a multiple of 2.
**User:** Which of the following has a value of 84?
A. 512
B. 83
C. 4,096
D. 32 **Weegy:** 4,096 has a value of 8^4. **User:** How can we tell if a number is divisible by 4?
A. The sum of the digits is divisible by 4
B. The last digit is divisible by 4
C. The sum of the digits is 4
D. The last two digits of the number are divisible by 4 **Weegy:** You can tell if a number is divisible by 4 if: The last two digits of the number are divisible by 4. **User:** What is the cube of 8?
A. 24
B. 2
C. 64
D. 512 **Weegy:** The cube of 8 is 512. **User:** Which of the following is a composite number?
A. 13
B. 31
C. 63
D. 61 **Weegy:** The answer is 63 **User:** Write 3 × 3 × 3 × 3 × 3 × 3 using exponents.
A. 123
B. 63
C. 36
D. 94 **Weegy:** 3 ? 3 ? 3 ? 3 ? 3 ? 3 using exponents is 3^6.
**User:** What is the square root of 81?
A. 11
B. 9
C. 18
D. 8 **Weegy:** The square root of 81 is 9.
**User:** Which of the following is a perfect square?
A. 13
B. 127
C. 100
D. 102 **Weegy:** The following is a perfect square: 100. **User:** Which of the following is a multiple of 4?
A. 734
B. 626
C. 891
D. 620 **Weegy:** The number 620 is a multiple of 4. **User:** Write 5 × 5 × 5 × 5 using exponents.
A. 55
B. 45
C. 54
D. 52 (More)

Question

Not Answered

Updated 10/14/2018 11:44:54 PM

1 Answer/Comment

5 × 5 × 5 × 5 using exponents is 5^4.

Added 10/14/2018 11:44:54 PM

This answer has been confirmed as correct and helpful.

Find the value of Z in the following equation: 8Z = 64.
A. 512
B. 72
C. 56
D. 8 **Weegy:** 8Z = 64 **User:** Solve the equation: 12y = 132.
A. y = 11
B. y = 1/11
C. y = 11/12
D. y = 144 **Weegy:** 12y = 132 **User:** What's the simplified form of x 1 + 4 + 7x 3?
A. 6x
B. 8x + 6
C. 8x
D. 6x + 3 (More)

Question

Updated 10/14/2018 11:43:04 PM

2 Answers/Comments

Simplify this expression: 4p + 9 + (–7p) + 2
A. 3p + 7
B. 3p + 11
C. –3p + 11
D. 11p + 11 **Weegy:** 4p + 9 + ( 7p) + 2 **User:** Given the formula D = ABC, what is the formula for C?
A. C = AD ÷ C
B. C = ABD
C. C = D ÷ AB
D. C = AB ÷ D **Weegy:** D = ABC **User:** Solve this inequality: 9h + 2 **Weegy:** 9h + 2 **User:** Simplify and solve this equation for q: 3q + 5 + 2q – 5 = 65.
A. q = 15
B. q = 11
C. q = 13
D. q = 23 **Weegy:** 3q + 5 + 2q - 5 = 65 (More)

Question

Updated 10/14/2018 11:44:15 PM

4 Answers/Comments

4p + 9 + (–7p) + 2 = 4p + 9 -7p +2 = -3p +11.

Added 10/14/2018 11:41:27 PM

This answer has been confirmed as correct and helpful.

Confirmed by alfred123 [10/14/2018 11:44:52 PM]

The formula D = ABC, the formula for C = D/AB.

Added 10/14/2018 11:41:42 PM

This answer has been confirmed as correct and helpful.

Confirmed by alfred123 [10/14/2018 11:45:08 PM]

9h + 2 < -79 , 9h < -79 -2 , 9h <-81 , h < -81/9 , h< -9.

Added 10/14/2018 11:42:00 PM

This answer has been confirmed as correct and helpful.

Confirmed by alfred123 [10/14/2018 11:45:31 PM]

What's the circumference of a circle with a diameter of 30 centimeters?
A. 188.4 centimeters
B. 94.2 centimeters
C. 9.55 centimeters
D. 47.1 centimeters

Question

Updated 4/25/2019 2:31:27 AM

1 Answer/Comment

The circumference of a circle with a diameter of 30 centimeters is: 94.2 centimeters.

Solution:

Circumference (c) = Diameter (d) * pi

c = 30 * 3.1416

c = 94.2.

Solution:

Circumference (c) = Diameter (d) * pi

c = 30 * 3.1416

c = 94.2.

Added 4/25/2019 2:31:27 AM

This answer has been confirmed as correct and helpful.

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