The empirical formula of a compound with 40%C, 6.7%H, 53.3%O is:

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Formula: % - moles - simplest ratio Convert to moles C: 40 / 12 = 3.333 H: 6.7 / 1 = 6.7 O: 53.3 / 16 = 3.331 Step 2: Divide by smallest moles (3.331) C: 3.333 / 3.331 = 1 H: 6.7 / 3.331 = 2 O: 3.331 / 3.331 = 1 Write empirical formula Empirical formula = CH2O Answer: CH2O

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Asked 32 days ago|1/12/2026 7:35:36 AM

Updated 32 days ago|1/12/2026 8:19:33 AM

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Flora1988

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Added 32 days ago|1/12/2026 8:00:50 AM

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Flora1988

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Added 32 days ago|1/12/2026 8:01:17 AM

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cruz30

Formula: % - moles - simplest ratio
Convert to moles
C: 40 / 12 = 3.333
H: 6.7 / 1 = 6.7
O: 53.3 / 16 = 3.331
Step 2: Divide by smallest moles (3.331)
C: 3.333 / 3.331 = 1
H: 6.7 / 3.331 = 2
O: 3.331 / 3.331 = 1
Write empirical formula
Empirical formula = CH2O
Answer:
CH2O

Added 32 days ago|1/12/2026 8:19:33 AM

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