If a ball with an original velocity of zero is dropped from a tall structure and takes 7 seconds to hit the ground, what velocity does the ball have when it reaches the ground?
Vf = Vi + at Vi = Initial velocity = 0 a = acceleration due to gravity = 9.8 m/s^2 t = time = 7 seconds Vf = 0 + (9.8)(7) Vf = 68.6 m/s.
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Question
Updated 87 days ago|7/31/2020 2:40:41 PM
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Vf = Vi + at
Vi = Initial velocity = 0
a = acceleration due to gravity = 9.8 m/s^2
t = time = 7 seconds
Vf = 0 + (9.8)(7)
Vf = 68.6 m/s.
Added 87 days ago|7/31/2020 2:40:41 PM

Questions asked by the same visitor
In a practical machine, the power output is smaller than the power input. Considering the law of energy conservation, what can explain this occurrence?
Question
Updated 90 days ago|7/28/2020 3:41:05 AM
Some of the energy is used to combat friction, and thus is transformed from mechanical energy to heat. -explains why power output is less than the power input in a practical machine, considering the law of energy conservation.
Added 90 days ago|7/28/2020 3:41:05 AM
In a practical machine, the power output is smaller than the power input. Considering the law of energy conservation, what can explain this occurrence? A. Some of the energy going into the machine is being destroyed. B. Some of the energy is used to combat friction, and thus is transformed from mechanical energy to heat. C. Some of the energy going into the machine is being created at a quicker rate than the energy coming out is being destroyed. D. Some of the energy coming out of the ...
Question
Updated 90 days ago|7/28/2020 3:41:40 AM
In a practical machine, the power output is smaller than the power input. [ Considering the law of energy conservation, Some of the energy is used to combat friction, and thus is transformed from mechanical energy to heat can explain this occurrence. ]
Added 90 days ago|7/28/2020 3:41:40 AM
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