Solve for x.
3(x + 5) - 2(x + 2) = 20
1
9
13

Question

Asked 9/14/2012 12:17:23 PM

Updated 9/14/2012 12:23:53 PM

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Question

Asked 9/14/2012 12:17:23 PM

Updated 9/14/2012 12:23:53 PM

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3(x + 5) - 2(x + 2) = 20

3x + 15 - 2x - 4 = 20

3x - 2x = 20 -15 + 4

x = 9

3x + 15 - 2x - 4 = 20

3x - 2x = 20 -15 + 4

x = 9

Added 9/14/2012 12:23:53 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/22/2014 9:36:20 AM]

Find the common difference of the sequence shown.
, , 0, ...
-1/8
-1/4
-1/2 **Weegy:** B.-1/4 is the answer. 1/2, 1/4 , 0, -1/4 is the sequence (More)

Question

Updated 8/28/2014 9:13:41 AM

1 Answer/Comment

The sequence 0,...-1/8, -1/4, -1/2 does not have a common difference, it has a common ratio.

Added 8/28/2014 9:13:41 AM

This answer has been confirmed as correct and helpful.

Which of the following equations has no solution?
3x+ 1 = 2x + 1
3x+ 1 = 3x+ 1
3x+ 1 = 3x+ 2 **Weegy:** 9x^4. If you are satisfied with my answer, please click 'Good' on the ratings. Thank you! (More)

Question

Updated 11/29/2014 10:05:01 PM

1 Answer/Comment

The equation 3x + 1 = 3x + 2 has no solution.

3x + 1 = 3x + 2;

3x - 3x = 2 - 1;

0 = 1

3x + 1 = 3x + 2;

3x - 3x = 2 - 1;

0 = 1

Added 11/29/2014 10:05:00 PM

This answer has been confirmed as correct and helpful.

Find two consecutive integers whose sum is 67.
Which of the following equations could be used to solve the problem?
2x= 67
2x+ 1 = 67
2x+ 2 = 67
x2+ 1= 67

Question

Updated 8/28/2014 9:30:22 AM

1 Answer/Comment

To find two consecutive integers whose sum is 67 use the equation 2x + 1= 67

Added 8/28/2014 9:29:48 AM

This answer has been confirmed as correct and helpful.

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