Question and answer
Which of the following is the correct factored form of the given equation? 4x^2 - 25 = 0 (4x - 5)(x + 5) = 0 (2x - 5)(2x + 5) = 0 2(x - 5)² = 0
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Asked 10/2/2012 9:41:08 PM
Updated 6/4/2014 12:51:45 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [6/4/2014 12:49:57 AM]
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User: Which of the following is the correct factored form of the given equation? 4x^2 - 25 = 0 (4x - 5)(x + 5) = 0 (2x - 5)(2x + 5) = 0 2(x - 5)² = 0

Weegy: quadratic formula always works
scijoe21|Points 2225|

User: Which of the following is the correct factored form of the given equation? 4x2 - 25 = 0 (4x - 5)(x + 5) = 0 (2x - 5)(2x + 5) = 0 2(x - 5)² = 0

User: What is the solution set of the following equation? 6x^2 = 13x + 5 {5/3, -1/2} {-1/3, 5/2} {-3, 2/5}

Weegy: 1. 3x - 2(3x +9) -34/3 2. 5 - 3(2y - 1) = 4 5 - 6y + 3 = 4 8 - 6y = 4 -6y = -4 y = 4/6 = 2/3 3. 4. -9x - 4 14/13 5. 2 + 5(w - 2) > 3w + 1 2 + 5w - 10 > 3w + 1 5w - 8 > 3w + 1 2w > 9 w > 9/2 6. [ 2(7x - 3) > 5(2x + 6) 14x - 6 > 10x + 30 4x > 36 x > 9 7. 10 - 3(2y - 4) = 5y + 2(y - 1) 10 - 6y + 12 = 5y + 2y - 2 -6y + 22 = 7y - 2 -13y = -24 y = 24/13 8. 2(2d - 3) - 5(2d + 3) > 4(3d - 8) 4d - 6 - 10d - 15 > 12d - 32 -6d - 21 > 12d - 32 -18d > -11 d < 11/18 ]
Expert answered|tereselast|Points 16|

Question
Asked 10/2/2012 9:41:08 PM
Updated 6/4/2014 12:51:45 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [6/4/2014 12:49:57 AM]
New answers
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8
4x^2 - 25 = 0
(2x - 5)(2x + 5) = 0
Added 6/4/2014 12:49:54 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/26/2014 12:00:37 AM]
8
6x^2 = 13x + 5
6x^2 - 13x - 5 = 0
(2x - 5)(3x + 1) = 0
x = 5/2 or x = -1/3
the solution set for the equation 6x^2 = 13x + 5 is {-1/3, 5/2}
Added 6/4/2014 12:51:45 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/26/2014 12:00:50 AM]
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