what is the value of x in the eqution (3x+2)/(2x-3)=(3x-2)/(2x-5) ?

The value of x in the eqution (3x+2)/(2x-3)=(3x-2)/(2x-5) is x = 8. (3x+2)/(2x-3) = (3x-2)/(2x-5) (3x + 2)(2x - 5) = (3x - 2)(2x - 3) 6x^2 + 4x - 15x - 10 = 6x^2 - 4x - 9x + 6 -11x - 10 = -13x + 6 -16 = -2x x = 8

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Asked 3/28/2010 9:33:08 PM

Updated 2/10/2015 1:48:43 AM

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The value of x in the eqution (3x+2)/(2x-3)=(3x-2)/(2x-5) is x = 8.

(3x+2)/(2x-3) = (3x-2)/(2x-5)

(3x + 2)(2x - 5) = (3x - 2)(2x - 3)

6x^2 + 4x - 15x - 10 = 6x^2 - 4x - 9x + 6

-11x - 10 = -13x + 6

-16 = -2x

x = 8

(3x+2)/(2x-3) = (3x-2)/(2x-5)

(3x + 2)(2x - 5) = (3x - 2)(2x - 3)

6x^2 + 4x - 15x - 10 = 6x^2 - 4x - 9x + 6

-11x - 10 = -13x + 6

-16 = -2x

x = 8

Added 2/10/2015 1:48:43 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [2/10/2015 3:22:19 AM]

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