Question and answer
Use the difference of two squares forumula to factor. 81x^2 - 1
Question
Asked 3/14/2013 11:20:55 PM
Updated 4/30/2015 2:52:10 AM
1 Answer/Comment
This answer has been confirmed as correct and helpful.
Edited by Andrew. [4/30/2015 2:52:08 AM], Confirmed by Andrew. [4/30/2015 2:52:10 AM]
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User: Use the difference of two squares forumula to factor. 4x^2 - 25

User: Use the difference of two squares forumula to factor. 81x^2 - 1

Weegy: Solution: 81x^2-1 = (9x)^2-1^2 = (9x+1)(9x-1) ; therefore the answer is (9x+1)(9x-1) .
Expert answered|armageddon|Points 398|

Question
Asked 3/14/2013 11:20:55 PM
Updated 4/30/2015 2:52:10 AM
1 Answer/Comment
This answer has been confirmed as correct and helpful.
Edited by Andrew. [4/30/2015 2:52:08 AM], Confirmed by Andrew. [4/30/2015 2:52:10 AM]
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3
4x^2 - 25

= (2x)^2 - 5^2

= (2x - 5)(2x + 5)
Added 4/30/2015 2:37:51 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [4/30/2015 2:52:19 AM]
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Questions asked by the same visitor
Add or substract the follow polynomials as indicated: (5.9x^3 +3.4x^2 - 7) - (2.9x^3 -9.6x^3) - (9.6x^2 + 3)
Weegy: (5.9x^3 +3.4x^2 - 7) - (2.9x^3 -9.6x^3 - 9.6x^2 + 3) = 12.6x^3+13.x^2-10 User: multiply. (6x +7)(3x+2) Weegy: (6x+7)(3x+2) = 18x^2+33x+14 User: Multiply. (4x + 1)(2x^2 + x + 1) Weegy: 5/2x+1/4x=7/4+x SOLUTION: 5/2x+1/4x-x=7/4 >> (5/2+1/4-1)x=7/4 >> (7/4)x=7/4 >> x=(7/4)/(7/4) >> x=1 (More)
Question
Updated 4/30/2015 2:33:25 AM
1 Answer/Comment
(4x + 1)(2x^2 + x + 1)
=8x^3+2x^2+4x^2+x+4x+1
=8x^3+6x^2+5x+1
Added 4/30/2015 2:33:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [4/30/2015 2:53:40 AM]
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