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Find the quotient. 48a3bc2 ÷ 3abc (a)16a4b2c3 (b)16a2c (c)18a2c (d)16ac2
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Asked 4/10/2012 4:10:31 PM
Updated 7/2/2014 12:18:12 PM
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User: Find the quotient. 48a3bc2 ÷ 3abc (a)16a4b2c3 (b)16a2c (c)18a2c (d)16ac2

Weegy: (a)16a4b2c3. 48a3bc2 ÷ 3abc = 16a4b2c3
Expert answered|migzptz|Points 5641|

Question
Asked 4/10/2012 4:10:31 PM
Updated 7/2/2014 12:18:12 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by jeifunk [7/2/2014 12:17:40 PM]
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48a^3bc^2 ÷ (3abc) = 16a^2c.
Added 7/2/2014 12:18:12 PM
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Perform the indicated operation. (c2 + 2c - 35) ÷ (c - 5) (a)c + 7 (b)c - 7 (c)c - 5
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Updated 7/9/2014 2:29:22 PM
1 Answer/Comment
(c^2 + 2c - 35) ÷ (c - 5) = [(c + 7)(c - 5)]/(c - 5) = c + 7
Added 7/9/2014 2:29:22 PM
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