x*(x-1)=42 , find x
x*(x - 1) = 42; x^2 - x = 42; x^2 - x - 42 = 0; (x + 6) (x - 7) = 0; x + 6 = 0; x = -6; x - 7 = 0; x = 7 Solutions: x = -6 or x = 7
Question
Updated 8/10/2014 5:05:10 PM
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x*(x - 1) = 42;
x^2 - x = 42;
x^2 - x - 42 = 0;
(x + 6) (x - 7) = 0;
x + 6 = 0; x = -6;
x - 7 = 0; x = 7
Solutions: x = -6 or x = 7

Questions asked by the same visitor
x*(x-1)=42
Weegy: Rule 1) The Derivative of any constant is always zero. You can know constants because they do not change with any variable. [ So if C never changes no matter what x (or any other variable) does, for example, then C is a constant and dC = C'(x) = 0 dx Examples: The number, 14, doesn't change no matter what else varies. So the derivative of 14 is zero. The value of p doesn't change no matter what else changes, so the derivative of p is always zero. If a circle of fixed size has radius, r, then r is constant and the derivative of r is zero. ] User: how much is x? User: x*(x-1)=42, how much is x? Weegy: 2x-1x = 42 x=42 (More)
Question
Updated 8/10/2014 9:40:23 PM
x*(x-1)=42
x^2-x-42=0
(x-7)(x+6) =0
x-7=0 or x+6=0
x=7 or x =-6
Confirmed by jeifunk [8/10/2014 9:41:50 PM]
39,228,221
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