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Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.
when x = 3/4, q(3/4) = 6(3/4)^3 + 19(3/4)^2 – 15(3/4) – 28 = -26, therefore, 3/4 is not a root for the function q(x) = 6x^3 + 19x^2 – 15x – 28.
Expert answered|yeswey|Points 11255|
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Asked 5/15/2014 7:54:19 AM
Updated 5/15/2014 9:38:34 AM
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This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/15/2014 9:38:34 AM]
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